We are given information:
m = 0.0450 kg
Δv = 25.2 m/s
Δt = 1.95 ms = 0.00195s
To find force we use formula:
F = m * a
a is acceleration. To find it we use formula:
a = Δv / Δt
a = 25.2 / 0.00195
a = 12923.1 m/s^2
Now we can find force:
F = 0.0450 * 12923.1
F = 581.5 N
To check the effect of the ball's weight on this movement we need to calculate it and then compare it to this force.
W = m * g
W = 0.0450 * 9.81
W = 0.44145 N
We can see that weight is much smaller than the applied force so it's influence in negligible.
For Newton's second law, the force F applied to the object of mass m will cause an acceleration a of the body:

So, the acceleration is

The object undergoes through this acceleration for 10 seconds, t=10 s. Since it is an accelerated motion, we can find its final velocity after 10 seconds:

where

is the initial velocity of the object, which is zero since it starts from rest.
Finally we can calculate the final kinetic energy of the object, which is given by
Answer:
800cm3
Explanation:
This is a general gas law question
Which has the relationship P1V1/T1 = P2V2/T2
P1= P1 in kPa
T1 = T1 in K
V1= 800cm3
V2=?
P2= 2* P1
T2= 2*T1
The volume of gas after the changes (V2), making it as the subject of formula
V2= P1*V1*T2/P2*T1
V2 = P1 *800* 2T1 / 2P1 * T1 ; dividing accordingly, we have
V2 = 800cm3
Answer:
So the force of attraction between the two objects is 3.3365*10^-6
Explanation:
m1=10kg
m2=50kg
d=10cm=0.1m
G=6.673*10^-11Nm^2kg^2
We have to find the force of attraction between them
F=Gm1m2/d^2
F=6.673*10^-11*10*50/0.1^2
F=3.3365*10^-8/0.01
F=3.3365*10^-6
AnswerA tell me what u got sorry if its worng
Explanation: