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Flura [38]
3 years ago
15

Particles q1, q2, and q3 are in a straight line. Particles q1 = -28.1 μC, q2 = +25.5 μC, and q3 = -47.9 μC. Particles q1 and q2

are separated by 0.300 m. Particles q2 and q3 are separated by 0.300 m. What is the net force on q3?
Physics
2 answers:
Arturiano [62]3 years ago
3 0

Answer:-88.4

Explanation:

Digiron [165]3 years ago
3 0

Answer:

-88.4

Explanation:

hope it helps

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With a diameter that's 11 times larger than Earth's, _______ is the largest planet.
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With a diameter that's 11 times larger than Earth's, Jupiter is the largest planet.

Jupiter is the biggest planet in the solar system. No wonder ancient astronomers named it after Jupiter, King of the Roman gods. More than 1,000 planets the size of Earth could fit inside Jupiter. A tunnel through Jupiter would be 11 times longer than a tunnel through Earth. A trip around Jupiter equator would take 6 times longer than a trip around the Earth's equator.
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An object moving at a constant velocity will always have a
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It will always have a zero acceleration

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Two electrons with a charge of magnitude 1.6×10-19 C in an atom are separated by 1.5×10-10 m, the typical size of an atom. What
vesna_86 [32]

Answer:

1.02\cdot 10^{-8} N, repulsive

Explanation:

The magnitude of the electric force between two charged particles is given by Coulomb's law:

F=k\frac{q_1 q_2}{r^2}

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k=8.99\cdot 10^9 Nm^{-2}C^{-2} is the Coulomb's constant

q_1, q_2 are the two charges of the two particles

r is the separation between the two charges

The force is:

- repulsive if the two charges have  same  sign

- Attractive if the two charges have opposite signs

In this problem, we have two electrons, so:

q_1=q_2=1.6\cdot 10^{-19}C is the magnitude of the two electrons

r=1.5\cdot 10^{-10} m is their separation

Substituting into the formula, we find the electric force between them:

F=(8.99\cdot 10^9)\frac{(1.6\cdot 10^{-19})^2}{(1.5\cdot 10^{-10})^2}=1.02\cdot 10^{-8} N

And the force is repulsive, since the two electrons have same sign charge.

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What will happen if a car experiences a 300 N force to the right from the engine and a separate 150 N force due to friction and
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Force applied on the car due to engine is given as

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Also there is a force on the car towards left due to air drag

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now the net force on the car will be given as

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now we can say that since the two forces are here opposite in direction so here the vector sum of two forces will be the algebraic difference of the two forces.

So we can say

F_{net} = F_1 - F_2

F_{net} = 300 - 150

F_[net} = 150 N

So here net force on the car will be 150 N towards right and hence it will accelerate due to same force.

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When will electric charges flow?
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C. when the circuit is closed
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