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vesna_86 [32]
3 years ago
5

If the frequencies of two component waves are 24 Hz and 20 Hz, they should produce _______ beats per second

Physics
2 answers:
Klio2033 [76]3 years ago
8 0
44 because you need to add 20+24 =44 beats per second
dimulka [17.4K]3 years ago
3 0
They should produce 44 beats per second 
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Radioactive carbon, or C-14, is used to date fossil remains. When C-14 decays, as seen in the nuclear equation, it produces what
olga nikolaevna [1]
The reaction of radiodecay of carbon C-14 is
C-14 --> N-14 + e- + (ve)
where e- is an electron and (ve) is an electron-type antineutrino.
Basically, when the carbon nucleus (atomic number: 6, mass number: 14) decays, a neutron of the nucleus converts into a proton (therefore, the mass number remains the same, 14, but the atomic number increases by 1, therefore it becomes nitrogen) and releases an electron-antineutrino pair. 

So, the correct answer is C), N-14.
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3 years ago
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What would happen if the distance between the earth and the moon decreased
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The gravitational force between earth and moon will increase.
by F = GMm/r^2
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3 years ago
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How can different objects interact when they are not even touching?
jeka94

Answer: Magnetic and gravitational force

Explanation: When a magnet and an iron nail are kept at a distance,the magnet attracts the nail without touching using magnetic force. In this example, the magnet and the nail are interacting.

The earth pulls the moon towards it and keeps it in orbit without touching it, using gravitational force. In this example,the moon and the earth are interacting.

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3 0
3 years ago
Science plz help meeee
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Answer:

The difference in these is that the ovary of a fruit can be edible which forms to enclose around seeds while a tree grows up to have a different structure and means of reproduction/

Explanation:

8 0
3 years ago
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An accelerating voltage of 2.47 x 10^3 V is applied to an electron gun, producing a beam of electrons originally traveling horiz
Dmitry [639]

Answer:

6.3445×10⁻¹⁶ m

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E = Accelerating voltage = 2.47×10³ V

m = Mass of electron

Distance electron travels = 33.5 cm = 0.335 cm

E=\frac{mv^2}{2}\\\Rightarrow v=\sqrt{\frac{2E}{m}}\\\Rightarrow v=\sqrt{\frac{2\times 2470\times 1.6\times 10^{-19}}{9.11\times 10^{-31}}}\\\Rightarrow v=29455356.08671\ m/s

Deflection by Earth's Gravity

\Delta =\frac {gt^2}{2}

Now, Time = Distance/Velocity

\Delta =\frac {g\frac{s^2}{v^2}}{2}\\\Rightarrow \Delta =\frac{9.81\frac{0.335^2}{29455356.08671^2}}{2}\\\Rightarrow \Delta =6.3445\times 10^{-16}\ m

∴ Magnitude of the deflection on the screen caused by the Earth's gravitational field is 6.3445×10⁻¹⁶ m

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