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3 years ago

What conclusions can be drawn about the existence of carbon-12, carbon-13, and carbon-14?

2 answers:

7 0

<span>These are isotopes of carbon and they all contain 6 protons and 6 electrons but each contains a difference number of neutrons - 6, 7, and 8 respectively.

^ This is the answer because an isotope changes the atomic mass, NOT atomic number. That means that the neutrons are changed, not the protons. </span>

mars1129 [50]3 years ago

3 0

Answer: These are isotopes of carbon and they all contain 6 protons and 6 electrons but each contains a difference number of neutrons - 6, 7, and 8 respectively.

Explanation: Isotopes of an element have similar number of protons but different number of neutrons.

General representation of an element is given as: $_Z^A\textrm{X}$ where,

Z represents Atomic number (for neutral atom) = number of protons= no of electrons

A represents Mass number = number of protons + number of neutrons

X represents the symbol of an element

Thus $_6^{12}\textrm{C}$ , $_6^{13}\textrm{C}$ and $_6^{14}\textrm{X}$ all contain same number of protons i.e 6 but contain (12-6) =6, (13-6)=7 and (14-6)=8 neutrons respectively.

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It is found that the most probable speed of molecules in a gas at equilibrium temperature

kaheart [24]

Answer:

$\frac{T_2}{T_1} = 1$

Explanation:

The root mean square velocity of the gas at an equilibrium temperature is given by the following formula:

$v = \sqrt{\frac{3RT}{M} }$

where,

v = root mean square velocity of molecules:

R = Universal Gas Constant

T = Equilibrium Temperature

M = Molecular Mass of the Gas

Therefore,

For T = T₁ :

$v = \sqrt{\frac{3RT_1}{M} }$

For T = T₂ :

$v = \sqrt{\frac{3RT_2}{M} }$

Since both speeds are given to be equal. Therefore, comparing both equations, we get:

$\sqrt{\frac{3RT_1}{M} }=\sqrt{\frac{3RT_2}{M} }\\\\\frac{T_2}{T_1} = 1$

8 0

3 years ago

Which of the following is NOT an exercise myth?

Blababa [14]

It is <span>C. Low to moderate level of exertion can be sustained over long periods of time </span>

7 0

2 years ago

A 17-mm-wide diffraction grating has rulings of 530 lines per millimeter. White light is incident normally on the grating. What

Sedbober [7]

Answer:

377 nm

Explanation:

Number of lines per meter is, $N &=530 \times 1000 \\ &=530000 \text { lines } / \mathrm{m} \end{aligned}$

Grating element is, $d=\frac{1}{N}$

$=1.8868 \times 10^{-6} \mathrm{~m}[tex]
Order is, n=5
Condition for maximum intensity is, [tex]d \sin \theta=n \lambda$

$\lambda &=\frac{1.8868 \times 10^{-6}}{5(\sin 90)} \\
&=0.377 \times 10^{-6} \mathrm{~m} \\
&=377 \mathrm{~nm}$

7 0

3 years ago

At what height does a 1000-kg mass have a potential energy of 1J relative to the ground? Be sure to show all work to support you

nikdorinn [45]

Potential energy = (mass) x (gravity) x (height)

1 joule = (1,000 kg) x (9.8 m/s²) x (height)

Height = 1 joule / (9,800 newtons)

= 1/9800 meter

= 0.000102 meter

= 0.102 millimeter (rounded)

7 0

3 years ago

When an ice cube is placed in a glass of warm water, how are the signs and values q for the ice and the warm water related, assu

Valentin [98]

Answer:

q(ice) = -q(warm water)

Explanation:

Ice removes energy if ice is put in warm water and ice retains the very same amount of energy. Thus the water temperature heat sign is negative, and the ice heat sign is positive.

3 0

3 years ago