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MAXImum [283]
3 years ago
10

Find the midpoint of segment with the following endpoint (2,3) and (-5,-2)

Mathematics
1 answer:
RideAnS [48]3 years ago
8 0

Answer:

(-1.5,0.5)

Step-by-step explanation:

In the attached file

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Choose the pair of numbers that is not a solution to the given equation.
balandron [24]

Answer:

The pair (0,3) is not a solution to the equation

Step-by-step explanation:

This can be proved by simply replacing the x and y variables in the equation by the x and y values of the pair, and checking if the equation renders a true statement:

By replacing x and y with their values in the pair (0,3), that is x=0 and y=3, in the equation y = 5 - 2x  we get:

3 = 5 - 2 (0)

3 = 5 - 0

3 = 5

which is NOT a true statement.

On the other hand, the other two pairs (2,1) and (1,3) render true statements:

1 = 5 - 2 (2)

1 = 5 - 4

1 = 1

and

3 = 5 - 2 (1)

3 = 5 - 2

3 = 3

3 0
3 years ago
In MON, J, K, and L are midpoints. If JL = 11, LK = 13, and ON = 20, and JL || MN, LK || MO, and JK || ON, what is the length of
In-s [12.5K]

Answer:

The lengths of MN is 22 units, MO is 26 units and JK is 10 units

Step-by-step explanation:

<em>A l</em><em>ine segment</em><em> joining the </em><em>mid-points of two sides</em><em> in a triangle is </em><em>parallel to the third side</em><em> and </em><em>equal to half its length</em>

In Δ MON

∵ J, K, and L are mid-points

∵ JL // MN and LK // MO

∴ L is the mid-point of ON

∴ J is the mid-point of MO

∴ K is the mid-point of MN

∵ J, L are the mid-points of MO and ON

∵ JL is opposite to MN

→ By using the rule above

∴ JL = \frac{1}{2} MN

∵ JL = 11 units

∴ 11 = \frac{1}{2} MN

→ Multiply both sides by 2

∴ 22 = MN

∴ MN = 22 units

∵ K, L are the mid-points of MN and ON

∵ KL is opposite to MO

→ By using the rule above

∴ KL = \frac{1}{2} MO

∵ KL = 13 units

∴ 13 = \frac{1}{2} MO

→ Multiply both sides by 2

∴ 26 = MO

∴ MO = 26 units

∵ J, K are the mid-points of MO and MN

∵ JK is opposite to ON

→ By using the rule above

∴ JK = \frac{1}{2} ON

∵ ON =20 units

∴ JK = \frac{1}{2} (20)

∴ JK = 10 units

∴ The lengths of MN are 22 units, MO is 26 units and JK is 10 units

3 0
3 years ago
Determine the probability of randomly selecting two individuals who are issued exactly two credit cards.​ [Hint: Are the events​
pishuonlain [190]

Answer:

They are dependent because we have to select from people who are given cards.

Step By Step Explanation:

So we'll take away people not given cards first den find the probability of selecting people with cards over the total number of people present .

Probability we'll be equal to = number of people with card(C) two persons/total number of people

Where C represent combination

5 0
3 years ago
A x 4 = E
lana [24]
A * 4 = E........A = E / 4
B / 4 = E........B = 4E
C + 4 = E......C = E - 4
D - 4 = E.......D = E + 4

A + B + C + D = 100
(E/4) + (4E) + (E - 4) + (E + 4) = 100
E/4 + 6E = 100 ....multiply by 4
E + 24E = 400
25E = 400
E = 400/25
E = 16 <===


7 0
3 years ago
Help on this please on 16
timama [110]

Answer:

Step-by-step explanation:B

8 0
3 years ago
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