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3 years ago

Which of these is the x-intercept of x = 3?

Mathematics

1 answer:

ehidna [41]3 years ago

8 0

(3,0)
0 is the point on the x-axis, it's not above or below the x-axis

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Write the rational number as a decimal -1/9

jarptica [38.1K]

$-\frac{1}{9} =-0.1111111111...$

8 0

2 years ago

Doris made 80 cookies this week. She baked 4 less than three times the total she made last week. Which equation, when solved for

sertanlavr [38]

Answer:

The equation is $3x-4=80$

The value of x is 28 cookies

Step-by-step explanation:

Let

x ----> the number of cookies she baked last week

we know that

The number of cookies she baked last week multiplied by 3 minus 4 must be equal to 80 cookies

The linear equation that represent this situation is

$3x-4=80$

solve for x

$3x=80+4\\3x=84\\x=28\ cookies$

3 0

3 years ago

Can someone pleaseeeeeehelp me

Effectus [21]

the answer will be bbcuz

7 0

3 years ago

Selena is 6 years younger than Paul. In 15 years, Paul will be 4 times the age that Selena is now. Find their present ages.

s344n2d4d5 [400]

Answer:

<u>The ages of Paul and Selena are 13 and 7 years old.</u>

Step-by-step explanation:

Age of Paul = x

Age of Selena = x -6

Age of Paul and Selena in 15 years:

x + 15 = 4 (x - 6)

x + 15 = 4x - 24

x - 4x = -24 - 15

- 3x = -39

x = 13

<u>Paul now is 13 years old and Selena is 7 years old. In 15 years, Paul will be 28, that is 4 times the present age of Selena.</u>

3 0

2 years ago

Read 2 more answers

Verify that -5, 1/2, and 3/4 are the zeroes of the cubic polynomial 4x^3+20x^2+2x-3. Also verify the relationship between the ze

Finger [1]

Solution:

we have been asked to verify that -5, 1/2, and 3/4 are the zeroes of the cubic polynomial $4x^3+20x^2+2x-3$

To verify that whether the given values are zeros or not we will substitute the values in the given Polynomial, if it will returns zero, it mean that value is Zero of the polynomial. But if it return any thing other than zeros it mean that value is not the zero of the polynomial.

Let $f(x)=4x^3+20x^2+2x-3\\\\\text{when x=-5}\\\\f(-5)=4(-5)^3+20(-5)^2+2(-5)-3=-13\\\\\text{when x=}\frac{1}{2}\\$

$f( \frac{1}{2} ) = 4 ( \frac{1}{2} )^3+20(\frac{1}{2})^2+2(\frac{1}{2})-3=\frac{7}{2}\\\\$

$\text{when x=}\frac{3}{4}\\\\$

$f( \frac{3}{4} ) = 4 ( \frac{3}{4} )^3+20(\frac{3}{4})^2+2(\frac{3}{4})-3=\frac{183}{16}\\$

Hence -5, 1/2, and 3/4 are not the zeroes of the given Polynomial.

Since sum of roots $=\frac{-b}{a}= \frac{-20}{4}=-5\\$

But $-5+\frac{1}{2}+\frac{3}{4}= \frac{-15}{4}\neq-5$

Hence we do not find any relation between the coefficients and zeros.

Anyway if the given values doesn't represents the zeros then those given values will not have any relation with the coefficients of the p[polynomial.

6 0

2 years ago