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m_a_m_a [10]
3 years ago
14

For a successful TLC experiment, you need to pay attention to the details. From the list of instructions and tips below, select

the detail that is NOT important to a TLC experiment. O O Do not disturb the developing chamber. Do not move it or carry around. Closely monitor the temperature of the solvent in the chamber. Use only a plain pencil to draw a starting line and mark the compounds' spots. A pen or marker should never be used. Cover the developing chamber with a watch glass. Ensure the solvent level in the chamber is lower than the starting line where you spot the samples.
Chemistry
1 answer:
Juli2301 [7.4K]3 years ago
5 0

Answer:

Temperature is not that important in TLC.

Explanation:

The concept of TLC is that a solvent (or mixture of solvents) ascends in a capilary system and the differences in interections between solvent and capilary of the substances present allow their separation.

In this process it's important that the air is saturated with solvent vapor, so the lid is important; the solvent must ascend by the capilar, so making it stedy is important, also making sure the starting line is above the solvent level is crucial for this same reason; using a marker would ruin a experiment because most marker's ink (if not all of them) would be carried by the solvent as well, but carbon is not, so a pencil must be used.

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What volumes of 0.200 M HCOOH and 2.00 M NaOH would make 500. mL of a buffer with the same pH as one made from 475 mL of 0.200 M
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<u>36 ml of NaOh and</u><u> 464 ml</u><u> of </u><u>HCOOH</u><u> would be enough to form 500 ml of a buffer with the same pH as the buffer made with </u><u>benzoic acid </u><u>and NaOH.</u>

What is benzoic acid found in?

  • Some natural sources of benzoic acid include: ​Fruits:​ Apricots, prunes, berries, cranberries, peaches, kiwi, bananas, watermelon, pineapple, oranges.
  • ​Spices:​ Cinnamon, cloves, allspice, cayenne pepper, mustard seeds, thyme, turmeric, coriander.

Calculate the amount of moles in NaOH and benzoic acid. This calculation is done by multiplying molarity by volume.

Amount of moles of NaOH -2 × 0.025 =  0.05 mol

Amount of moles of benzoic acid 2 × 0.475 = 0.095 mol

In this case, we can calculate the pH produced by the buffer of these two reagents, as follows

pH = pKa + log\frac{base}{acid}

4.2 + log\frac{0.05}{0.045} = 4.245

We must repeat this calculation, with the values shown for HCOOH and NaOH. In this case, we can calculate as follows

pH = pKa + log\frac{base}{acid}

4.245 = 3.75 + log\frac{base}{acid}

log\frac{base}{acid} = 0.5

\frac{base}{acid} = 3.162

Now we must solve the equation above. This will be done using the following values

\frac{2(0.5 - x)}{0.2x - 2(0.5 - x)} = 0.464 L

With these values, we can calculate the volumes of NaOH and HCOOH needed to make the buffer.

NaOH volume

( 0.5 - 0.464)L

0.036L .................... 36ml

HCOOH volume

500 - 36 = 464mL

Learn more about benzoic acid

brainly.com/question/24052816

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