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Paladinen [302]
3 years ago
8

In the hydrogenation of oils the catalyst used is: A. PtB. Ni C. FeD. V2O5​

Chemistry
1 answer:
natima [27]3 years ago
5 0

Answer:

B

Explanation:

plz follow me and give brainliest

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Do you expect potassium iodide to be soluble in cyclohexane
Allushta [10]
Answer is: no, <span>potassium iodide has low solubility in cyclohexane.
</span>Potassium iodide (KI) is ionic compound, salt, that dissolve good in polar solvents (for example water), but it is very low soluble in non-polar solvents (in this example cyclohexane C₆H₁₂).
<span>Cyclohexane has zero net polarity, because it is a symmetric molecule, with sp2 hybridization of carbon.</span>
8 0
4 years ago
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How many atoms of oxygen are present in 7.51 grams of<br> glycine with formula C₂H5O2N?
Blizzard [7]

1.205 × 10²³ atoms of oxygen will be present in 7.51 grams of glycine with formula C₂H5O2N. Details about number of atoms can be found below.

How to calculate number of atoms?

The number of atoms of a substance can be calculated by multiplying the number of moles of the substance by Avogadro's number.

However, the number of moles of oxygen in glycine can be calculated using the following expression:

Molar mass of C₂H5O2N = 75.07g/mol

Mass of oxygen in glycine = 32g/mol

Hence; 32/75.07 × 7.51 = 3.2grams of oxygen in glycine

Moles of oxygen = 3.2g ÷ 16g/mol = 0.2moles

Number of atoms of oxygen = 0.2 × 6.02 × 10²³ = 1.205 × 10²³ atoms

Therefore, 1.205 × 10²³ atoms of oxygen will be present in 7.51 grams of glycine with formula C₂H5O2N.

Learn more about number of atoms at: brainly.com/question/8834373

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3 0
2 years ago
A 5.00 mL of a salt solution of unknown concentration was mixed with 35.0 mL of 0.523 M AgNO3. The mass of AgCl solid formed was
Lapatulllka [165]

Answer:

The chemical term in the equation for the precipitate of AgCl(s) is n=3.54*10^-3

Explanation:

the quantity of AgCl(s) in moles is:

n = 0.508g / 143.32 g/mol = 3.54*10^-3 mol

to verify it the mass of AgNO3 involved in the reaction should be

n AgNO3 required = n = 3.54*10^-3 mol

the mass of n involved should be higher than n AgNO3

n existing = V*N = 0.523 mol/L * 35*10^-3 L = 18.305*10^-3 mol

5 0
3 years ago
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Which statements accurately describe osmosis?
Serhud [2]

Answer:

Osmosis is a type of passive transport. The best statement that accurately describes osmosis is: Osmosis is the diffusion of water across a membrane.

Explanation:

7 0
3 years ago
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PLEASE HELP. What volume of 0.050 M of KOH neutralizes 200. mL of 0.0100 M HNO3?
dangina [55]
I think it’s B .. not sure
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3 years ago
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