Answer:
The answers are in the explanation
Explanation:
A buffer is the mixture of a weak acid with its conjugate base or vice versa. Thus:
<em>1)</em> Mixing 100.0 mL of 0.1 M HF with 100.0 mL of 0.05 M mol KF. <em>Will </em>result in a buffer because HF is a weak acid and KF is its conjugate base.
<em>2)</em> Mixing 100.0 mL of 0.1 M NH₃ with 100.0 mL of 0.1 M NH₄Br. <em>Will not </em>result in a buffer because NH₃ is a strong base.
<em>3) </em>Mixing 100.0 mL of 0.1 M HCN with 100.0 mL of 0.05 M KOH. <em>Will </em>result in a buffer because HCN is a weak acid and its reaction with KOH will produce CN⁻ that is its conjugate base.
<em>4)</em> Mixing 100.0 mL of 0.1 M HCl with 100.0 mL of 0.1 M KCl <em>Will not </em>result in a buffer because HCl is a strong acid.
<em>5)</em> Mixing 100.0 mL of 0.1 M HCN with 100.0 mL of 0.1 M KOH <em>Will not </em>result in a buffer because each HCN will react with KOH producing CN⁻, that means that you will have just CN⁻ (Conjugate base) without HCN (Weak acid).
I hope it helps!
8.24g
Explanation:
Given parameters;
Mass of NH₃ = 10g
Unknown:
Mass of N₂ = ?
Solution:
Reaction equation:
N₂ + 3H₂ → 2NH₃
Step 1: Convert 10.0 g of NH₃ into moles of NH₃
number of moles = 
molar mass of NH₃ = 14 + 3(1) = 17g/mol
Number of moles =
= 0.59mole
Step 2: Convert the moles of NH₃ calculated in Step 1 into moles of N₂
1 mole of N₂ produced 2 mole of NH₃
0.59 moles of ammonia would be formed by
mole = 0.29mole of N₂
Step 3: Convert the moles of N₂ calculated in Step 2 into grams of N₂.
Mass of N₂ = number of moles x molar mass
Molar mass of N₂ = 14 x 2 = 28g/mol
Mass of N₂ = 0.29 x 28 = 8.24g
learn more:
Number of moles brainly.com/question/1841136
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Answer:
20 grams
Explanation:
40g= 300
x = 150
cross multiply, 40*150/300
6000/300= 20g
Answer:
c) 1.07 M C6H1206
Explanation:
Molarity is the molar concentration of a solution, which is glucose in this case. It can be calculated using the following formula:
Molarity (M) = number of moles (n) ÷ volume (V)
Using mole = mass/molar mass, to calculate the number of moles of glucose in the solution, where mass = 125grams and MM = 180.16g/mol
mole = 125/180.16
mole = 0.694mol
Volume = 650.0 mL = 650/1000 = 0.650 L
Molarity = n/V
Molarity = 0.694/0.650
Molarity = 1.07 M
Answer:
Partial pressure of Ne = 366 mmHg
Explanation:
In a mixture, the sum of partial pressures for each gas, is the total pressure for the system.
Partial pressure He: 43 mmHg
Partial pressure Ar: 835 mmHg
Partial pressure Xe: 111 mmHg
Partial pressure Ne: ?
Total pressure = 1355 mmHg
43 + 835 + 111 + x = 1355
989 + x = 1355
x = 1355 - 989 → 366