Take 10m/s^2 for the gravitational acceleration, as we know this is a free fall, we can use the equation: d=1/2*g*t^2
Substitute g=10m/s^2, t=5s, d=125m
Answer:
Explanation:
The moon is a natural satellite of the earth, which performs rotational and revolutionary motions simultaneously. As the earth rotates about its axis, the moon rotates round it. But revolves round the Sun, as the earth also revolves round the Sun.
The motion of the moon causes series of its phases. Some major phases of the moon are, new moon, 1st quarter, full moon, and 3rd quarter (last quarter).
Since the moon reflects the light from the Sun, the face of the moon reflecting the light from the Sun changes gradually with respect to its motion.
At new moon, the face of the moon reflect no light. But reflects 100% at full moon. While both 1st and 3rd quarters show partial reflections.
Answer:
v = 17.30 m / s
Explanation:
For this exercise we will use Newton's second law
at the bottom of the loop and stopped
∑ F = 0
N-W = 0
N = W
W = 770 N
the mass of the body is
W = mg
m = W / g
m = 770 / 9.8
m = 78.6 kg
on top of the loop and moving
∑ F = m a
N + W = m a
note that the three vectors go in the same vertical direction down
the centripetal acceleration is
a = v² / r
we substitute
N + W = m v² / r
v = 
let's calculate
v = 
v = 17.30 m / s
Explanation:
Not enough information. It really depends on the technical details of the car ( the data provided is offering just the human factor of the reaction, not the time for getting the impulse through when using the breaks
Answer: he did travel 15 meters.
Explanation:
We have the data:
Acceleration = a = 1.2 m/s^2
Time lapes = 3 seconds
Initial speed = 3.2 m/s.
Then we start writing the acceleration:
a(t) = 1.2 m/s^2
now for the velocity, we integrate over time:
v(t) = (1.2 m/s^2)*t + v0
with v0 = 3.2 m/s
v(t) = (1.2 m/s^2)*t + 3.2 m/s
For the position, we integrate again.
p(t) = (1/2)*(1.2 m/s^2)*t^2 + 3.2m/s*t + p0
Because we want to know the displacementin those 3 seconds ( p(3s) - p(0s)) we can use p0 = 0m
Then the displacement at t = 3s will be equal to p(3s).
p(3s) = (1/2)*(1.2 m/s^2)*(3s)^2 + 3.2m/s*3s = 15m
