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lisov135 [29]
3 years ago
5

A long distance runner sees the finish line and accelerates at a rate in 1.2 m/s2 for

Physics
1 answer:
Nuetrik [128]3 years ago
6 0

Answer: he did travel 15 meters.

Explanation:

We have the data:

Acceleration = a = 1.2 m/s^2

Time lapes = 3 seconds

Initial speed = 3.2 m/s.

Then we start writing the acceleration:

a(t) = 1.2 m/s^2

now for the velocity, we integrate over time:

v(t) = (1.2 m/s^2)*t + v0

with v0 = 3.2 m/s

v(t) = (1.2 m/s^2)*t + 3.2 m/s

For the position, we integrate again.

p(t) = (1/2)*(1.2 m/s^2)*t^2 + 3.2m/s*t + p0

Because we want to know the displacementin those 3 seconds ( p(3s) - p(0s)) we can use p0 = 0m

Then the displacement at t = 3s will be equal to p(3s).

p(3s) = (1/2)*(1.2 m/s^2)*(3s)^2 + 3.2m/s*3s = 15m

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8. If the mass of a balloon is 300 kg and the lift force provided by the atmosphere is 3300 N, what
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Answer:

Toward the north, 300 N

Explanation:

Consider the upward direction as positive and downward direction as negative.

Given:

Mass of the balloon is, m=300\ kg

Lift force on the balloon in the upward direction is, F_L=3300\ N

Take acceleration due to gravity as 10 N/kg.

Now, weight of the balloon acting downward is given as the product of its mass and acceleration due to gravity. Therefore,

Weight is, W=mg=(300\ kg)(10\ N/kg)=-3000\ N

Now, net force is given as the vector sum of both the forces.

F_{net}=F_L+W\\F_{net}=3300-3000=300\ N(\textrm{Upward direction})

The upward direction is the direction of North. So, the net force acting on the balloon is 300 N towards North.

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D. A low lambda, λ, and a high nu, ν

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