Answer:
4.5 x 10^6 miles
Calculations can be viewed on the snapshot attached to this reply.
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While discussing electronic gasoline injection systems, Technician A states that most multiport EFI systems use two injectors fo
1 answer:
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Answer:
121Sb=57.2%
123Sb=42.8%
Explanation:
We are given that
Atomic mass of 121Sb=120.904 amu
Atomic mass of 123Sb=122.904 amu
Average atomic mass of antimony=121.760 amu
We have to find the percent of each of the isotope.
Let x be the percent of 121Sb and 1-x be the percent of 123Sb.
Using formula of average atomic weight
Average atomic weight=atomic weight of 121Sb percentage abundance of isotope 121Sb+atomic weight of 123Sb
percentage abundance of isotope 123Sb
Substitute the values
Percentage of 121Sb=57.2%
Abundance of isotope 123Sb=1-0.572=0.428
Percentage of isotope 123Sb=42.8%