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Vikki [24]
3 years ago
14

While discussing electronic gasoline injection systems, Technician A states that most multiport EFI systems use two injectors fo

r each engine cylinder. Technician B says such a system uses only one injector per engine cylinder. Who is right?
Physics
1 answer:
lutik1710 [3]3 years ago
8 0

Answer:Technician  B is right.

Explanation: A multi port  system is an advanced  type of Electronic Fuel Inection system that uses one injection per cylinder.  The microcontroller which is a part in the automated system of the Multi port system is responsible for monitoring and controlling the fuel injection process leading to fuel efficiency.

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A 5.22×104 kg railroad car moves on frictionless horizontal rails until it hits a horizontal spring stopper with a force constan
In-s [12.5K]

To solve this problem we will apply the principles of conservation of energy, for which we have to preserve the initial kinetic energy as elastic potential energy at the end of the movement. If said equality is maintained then we can affirm that,

\text{Initial Energy}=\text{Final Energy}

\frac{1}{2} mv^2=\frac{1}{2} kx^2

Here,

m = mass

k = Spring constant

x = Displacement

v = Velocity

Rearranging to find the velocity,

mv^2 = kx^2

v^2 = \frac{kx^2}{m}

v = \sqrt{\frac{kx^2}{m}}

Our values are,

m = 5.22*10^4kg

k = 4.58*10^5N/m

x = 32cm = 0.32m

Replacing our values we have,

v = \sqrt{\frac{(4.58*10^5)(5.22*10^4)}{0.32}}

v = 2.733*10^5m/s

Therefore the velocity is 2.733*10^5m/s

8 0
3 years ago
Which is NOT a property of magnetic field lines?
salantis [7]
The answer would be B. Magnetic fields are invisible they cannot be directly observed
4 0
3 years ago
Read 2 more answers
The psychologist known for latent learning and cognitive maps is _________. A. Robert Rescorla B. Edward Tolman C. William James
Lubov Fominskaja [6]

Answer:

B

Explanation:

B. Edward Tolman

4 0
3 years ago
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Which phase of cell division results in the formation of 4 new haploid cells
Alexandra [31]
The answer to your question is Meiosis.

Hope this helps! God bless
-vf
7 0
3 years ago
A roundabout in a fairground requires an input power of 2.5 kW when operating at a constant angular velocity of 0.47 rad s–1 . (
natita [175]

Answer:

Explanation:

Since the roundabout is rotating with uniform velocity ,

input power = frictional power

frictional power = 2.5 kW

frictional torque x angular velocity = 2.5 kW

frictional torque x .47 = 2.5 kW

frictional torque = 2.5 / .47 kN .m

= 5.32 kN . m

= 5 kN.m

b )

When power is switched off , it will decelerate because of frictional torque .

5 0
2 years ago
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