Answer:
I can't do the area but area of a triangle is
A of triangle = h×b over 2
h = hieght of the triangle
b= base of the triangle
You will have to use trial and error in order to find the values for x and y.
Just keep plugging values until you get 7.
I found x is equal to 2 and y is equal to 5.
3(2) + (1/5)5 = 7
6 + 5/5 = 7
6 + 1 = 7
7 = 7
I’m not too sure of what the equation is but I made a guess let me know if this was the right equation please I can redo it.
But, when solving this equation you are trying to find the value of x. To do that you have to get rid of the 3.
You would either add or subtract the 3 on both sides.
When the three is gone you should have somthing like
x = 5
- 3
Which you would move on to subtract the 5-3 and get 2.
x= 2
Here’s a picture of how I solved it
The X and Y angles created by lines intersection in the pictures are 18° and 54°.
Based on the picture, angle ∠MON is a right angle hence it has an 90° angle. We then know that the ∠MOA is 72°. Because angle ∠MOA lies within the angle ∠MON, hence we can write the following formula:
∠MON = ∠MOA +∠AON = 90°
∠MON = 72° + ∠AON = 90°
∠AON = 18° ... (i)
If we focus on the line CD being intersected by the line AB, hence we can conclude that the angles form by this intersection will follow these rules:
∠AOD = ∠BOC
∠AOC = ∠BOD
∠AOD + AOC = 180°
∠BOC + ∠BOD = 180°
Based on the picture, we know that:
∠BOC = x
∠AOC = ∠MOA + ∠MOC
∠AOC = 72° + y ...(ii)
∠AOD = ∠AON + ∠NOD
∠AOD = 18° +2x
∠BOC = 3x ... (iii)
Because we already know that ∠BOC = AOD, hence we could rewrite the formula into:
∠BOC = ∠AOD
3x = 18° + 2x
x = 18° ... (iv)
To find the value of y, we need to focus on angle ∠AOC. Based on the previous calculations and formulas, we know that:
∠AOC + ∠BOC = 180° ... (v)
Input equations (ii) and (iv) into (v)
∠AOC + ∠BOC = 180°
(72° + y) + 3x = 180°
72° + y + 3(18°) = 180°
126° + y = 180°
y = 54° ... (vi)
Learn more about the angles by lines intersection here: brainly.com/question/2077876?referrer=searchResults
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