Answer:
Mah dood! I gatchu! Dae ansa iz A! I gatchu fam! I gatchu Brochacho!
Explanation:
Tell me why i got this question got it right and now won’t remember but i’ll get back at you when i remember
16 unplug
18 surge?
19 flowing/conductive?
20 ear protection?
Answer:
n this question, we are asked to find the probability that
R1 is normally distributed with mean 65 and standard deviation 10
R2 is normally distributed with mean 75 and standard deviation 5
Both resistor are connected in series.
We need to find P(R2>R1)
the we can re write as,
P(R2>R1) = P(R2-R1>R1-R1)
P(R2>R1) = P(R2-R1>0)
P(R2>R1) = P(R>0)
Where;
R = R2 - R1
Since both and are independent random variable and normally distributed, we can do the linear combinations of mean and standard deviations.
u = u2-u1
u = 75 - 65 = 10ohm
sd = √sd1² + sd2²
sd = √10²+5²
sd = √100+25 = 11.18ohm
Now we will calculate the z-score, to find P( R>0 )
Z = ( X -u)/sd
the z score of 0 is
z = 0 - 10/11.18
z= - 0.89
