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Pachacha [2.7K]
3 years ago
15

An alloy to be used for a spring application must have a modulus resilience of at least 0.79 x 106 J/m3 (0.79 x 106 Pa). What mu

st be its minimum yield strength (in MPa)? Assume that the modulus of elasticity for this alloy is 102 GPa
Using Ur=Sig^2/2E, I am getting 401.447E6 Mpa but apparently thats wrong.
Engineering
1 answer:
xxTIMURxx [149]3 years ago
3 0

Answer:

4.13 MPa

Explanation:

Given

Modulus of elasticity = E = 102 GPa

E = 102 * 10^9

Modulus resilience U = 0.79 * 106Pa

Modulus of Resilience U = y²/2E --- Make y the subject of formula

y² = 2EU

y = √(2EU)

y = √(2 * 102 * 10^9 * 0.79 * 106)

y = √1.708296E13

y = 4133153.759540044

y = 4.13E6

y = 4.13MPa

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2. What is the charge, expressed in micro coulombs on two equally and similarly charges spheres placed in air with their centres
9966 [12]

Answer:

q = 0.1086 micro Coulombs

Explanation:

By Coulombs law, we have;

F =k \times  \dfrac{ q_1 \times q_2}{r^2}

Where;

F = The electric force = 120 mgm

q₁ and q₂ = Charge

r = The separating distance = 30 cm = 0.3 m

k = 8.9876×10⁹ kg·m³/(s²·C²)

Where, q₁ and q₂, we have;

F =k \times  \dfrac{ q^2}{r^2}

Whereby the force is the force of 120 milligram mass, we have;

0.00012 × 9.81 = 000011772 N

q = \sqrt{ \dfrac{ F\times r^2}{k}}

Substituting the values, we have;

q = \sqrt{ \dfrac{ 000011772 \times (0.3)^2}{8.9876 \times 10^9}} = 1.086 \times 10 ^{-7} \ Coulombs

q = 0.1086 micro Coulombs.

5 0
3 years ago
Determine the carburizing time necessary to achieve a carbon concentration of 0.30 wt% at a position 4 mm into an iron–carbon al
Ahat [919]

Answer:

the carburizing time necessary to achieve a carbon concentration is 31.657 hours

Explanation:

Given the data in the question;

To determine the carburizing time necessary to achieve the given carbon concentration, we will be using the following equation:

(Cs - Cx) / (Cs - C0) = ERF( x / 2√Dt)

where Cs is Concentration of carbon at surface = 0.90

Cx is Concentration of carbon at distance x = 0.30 ; x in this case is 4 mm = ( 0.004 m )

C0 is Initial concentration of carbon = 0.10

ERF() = Error function at the given value

D = Diffusion of Carbon into steel

t = Time necessary to achieve given carbon concentration ,

so

(Cs - Cx) / (Cs - C0) = (0.9 - 0.3) / (0.9 - 0.1)

= 0.6 / 0.8

= 0.75

now, ERF(z) = 0.75; using ERF table, we can say;

Z ~ 0.81; which means ( x / 2√Dt) = 0.81

Now, Using the table of diffusion data

D = 5.35 × 10⁻¹¹ m²/sec at (1100°C) or 1373 K

now we calculate the carbonizing time by using the following equation;

z = (x/2√Dt)

t is carbonizing time

so we we substitute in our values

0.81 = ( 0.004 / 2 × √5.35 × 10⁻¹¹ × √t)

0.81 = 0.004 / 1.4628 × 10⁻⁵ × √t

0.81 × 1.4628 × 10⁻⁵ × √t = 0.004

1.184868 × 10⁻⁵ × √t = 0.004  

√t = 0.004 / 1.184868 × 10⁻⁵

√t = 337.5903

t = ( 337.5903)²  

t = 113967.21 seconds

we convert to hours

t = 113967.21 / 3600

t = 31.657 hours

Therefore, the carburizing time necessary to achieve a carbon concentration is 31.657 hours

7 0
3 years ago
Explain why the scenario below fails to illustrate an understanding of the importance of metrology. Situation: Natalie is a cali
VMariaS [17]

Answer:

Explanation:

The situation being described completely fails in regard to the importance of metrology. This is because the main importance of metrology is making sure that all of the measurements in a process are as accurate as possible. This accuracy allows an entire process to function efficiently and without errors. In a food production plant, each individual department of the plant relies on the previous function to have completed their job with the correct and accurate instructions so that they can fulfill their functions correctly and end up with a perfect product. If the oven (like in this scenario) is a couple of degrees off it can cause the product to come out burned or undercooked, which will then get transferred to the next part of production which will also fail due to the failed input (burned or undercooked product). This will ultimately lead to an unusable product at the end of the process and money wasted. Which in a large production plant means thousands of products in a single batch are thrown away.

8 0
3 years ago
Assume a program contains a void function named calcNewPrice(). The function receives two double variables named oldPrice and ne
liberstina [14]

Answer:

(C) calcNewPrice(oldPrice, &newPrice);

Explanation:

It's a void function so there's no return value, however they wanted to change a value. The only way to do that is to pass in an address of the variable into the function, and deference it and store the new data there.

4 0
3 years ago
Assume that a specific hard disk drive has an average access time of 16ms (i.e. the seek and rotational delay sums to 16ms) and
djyliett [7]

Answer:

Average access time for a hard disk = 11.38 ms

Explanation:

See attached pictures for step by step explanation.

5 0
4 years ago
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