Answer:
4. Because they include the static heads plus the friction
Bias or persuasion perhaps
Hope this helps!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
The efficiency of this ideal and reversible engine is 85 percent.
The efficiency of the Carnot cycle represents the efficiency of a thermal machine with no irreversibilities, hence, it is impossible for any real engine operating between the two reservoirs cannot be more efficient than this engine.
Explanation:
Let assume that the temperature of the atmosphere is 300 K. From Thermodynamics we know that the efficiency of the Carnot's cycle (), dimensionless, is:
(1)
Where:
- Temperature of the kerosene combustor (hot reservoir), measured in kelvins.
- Temperature of the atmosphere (cold reservoir), measured in kelvins.
If we know that and , then the efficieny of this ideal and reversible engine is:
The efficiency of this ideal and reversible engine is 85 percent.
The efficiency of the Carnot cycle represents the efficiency of a thermal machine with no irreversibilities, hence, it is impossible for any real engine operating between the two reservoirs cannot be more efficient than this engine.
Given Information:
Current of Ideal source = Is = 100 mA = 0.100 A
Open circuit voltage = Voc = 6 V
Short circuit current = Isc = 200 mA = 0.200 A
Required Information:
Power absorbed by idea current source = ?
Answer:
Power absorbed by idea current source = 0.3 Watts
Explanation:
Ideal Current Source:
An ideal current source doesn't have internal resistance and provides constant current regardless of the voltage supplied to the circuit.
The power absorbed by the ideal source can be found using
P = Is²R
Where Is is the ideal source current and R can be found using
R = Voc/Isc
Where Voc is the open circuit voltage and Isc is the short circuit current.
R = 6/0.200
R = 30 Ω
Therefore, the power absorbed by the ideal current source is
P = Is²R
P = (0.100)²*30
P = 0.3 Watts