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ivanzaharov [21]
3 years ago
6

Can someone help me

Mathematics
2 answers:
galina1969 [7]3 years ago
7 0

The product of 6 and y is 6y. Then you add 15 to get 6y+15


olganol [36]3 years ago
7 0

Answer:9



Step-by-step explanation:


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-1/5

Step-by-step explanation:

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3 years ago
In ΔJKL, k = 3.7 cm, ∠K=15° and ∠L=41°. Find the length of j, to the nearest 10th of a centimeter.
Alexandra [31]

Answer:

The length of side j is 11.85cm

Step-by-step explanation:

Given that

In triangle JKL,

\angle k=15

\angle l=41

Side k=LJ=3.7cm

To find side j=KL:

By using sine rule,

We can write as

\frac{SinK}{LJ} = \frac{SinL}{JK} = \frac{SinJ}{KL} \\\frac{Sin15}{3.7} = \frac{Sin41}{JK} = \frac{SinJ}{KL}

Using property of triangle,

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\frac{Sin15}{3.7} = \frac{Sin41}{JK} = \frac{Sin124}{KL}\\\frac{Sin15}{3.7} = \frac{Sin124}{KL}\\KL=3.7\frac{Sin124}{Sin15}\\KL=3.7\frac{0.8290}{0.2588}\\KL=11.85cm

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The length of side j is 11.85cm

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3 years ago
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280 ÷ 0.04 = 7000

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