Let
be the set of all students in the <u>c</u>lassroom.
Let
and
be the sets of students that pass <u>p</u>hysics and <u>m</u>ath, respectively.
We're given




i. We can split up
into subsets of students that pass both physics and math
and those that pass only physics
. These sets are disjoint, so

ii. 9 students fails both subjects, so we find

By the inclusion/exclusion principle,

Using the result from part (i), we have

and so the probability of selecting a student from this set is

The slope of the line that passes through the points (-20,18) and (30,14) is
m (slope) = -2/25
Answer:
a=6
Step-by-step explanation:
to find the value of a you need to simplify the equation first. so...
3(a+3)-6=21 (you remove the bracket first)
3a+9-6=21
3a+3=21 (you collect the like terms then)
3a=21-3
3a=18 (then you both divide both sides by 3 to find the value of a)
a=18/3
a=6
to check your answer substitute 3 instead of a
3(a+3)-6=21
3(6+3)-6=21
3(9)-6=21 (according to BODMAS since multiplication comes first you multiply 3 with 9 before subtracting it from 6.)
29-6=21
21=21
Answer:
320,000 is the answer
Step-by-step explanation:
have a good day!!