Ok... let's break it apart and put it back together.
There's an absolute value... "2x-4" is inside the absolute value. The absolute value of "2x-4" is equal to the value of 8... so find x.
There are TWO cases:
(2x-4)=8
OR
-(2x-4)=8
Now you should be able to solve it. If you can't... well, just ask me below. I can't do ALL the work, can I?
:P
Answer:
I believe the answer is D
Step-by-step explanation:
Answer:
Yes.
Step-by-step explanation:
In the Quadratic Equation, <em>y</em><em> </em><em>=</em><em> </em><em>Ax</em><em>²</em><em> </em><em>+</em><em> </em><em>Bx</em><em> </em><em>+</em><em> </em><em>C</em><em>,</em><em> </em>two things could happen with your <em>A</em>:
Opens down → Maximum Value [-A]
Opens up → Minimum Value [A]
We can identify the minimum or maximum value of a parabola by identifying the y-coordinate of the vertex. You can use a graph to identify the vertex or you can find the minimum or maximum value algebraically by using the formula x = ⁻ᵇ/₂ₐ. This formula will give you the x-coordinate of the vertex.
I am joyous to assist you anytime.
Answer:
the game must be played in groups of 13 draws, with a cost of $28 for the 13 draws.
Step-by-step explanation:
Probability of drawing any of the 13 balls is the same. So the expected value of play is the average of the values of each card.
The only losing card is the ace; the player loses $20 if that card is drawn.
Each of the 3 face cards wins $10; each of the remaining 9 cards wins $2.
So the average value of each draw is
= 28/13
Therefore, on average the player will win $ 28/13. to be a fair game the player must pay $28/13 for a game.
that is not possible, unless the game must be played in groups of 13 draws, with a cost of $28 for the 13 draws.
