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diamong [38]
3 years ago
9

How is Hydrogen in heavy water different from hydrogen in normal water​

Chemistry
1 answer:
soldier1979 [14.2K]3 years ago
7 0

Answer: An oxygen atom in heavy water has an extra neutron. A hydrogen atom in heavy water has an extra proton.

Explanation:

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Complete the following paragraph.
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Explanation:

the stationary phase in TLC is a <u>silica gel coated metal plate or paper</u>.

The<u> individual</u> component of the mixure will travel a greater distance up the plate, resulting in a <u>Rf</u> value for the component.

the <u>p-Xylene  spot </u> will travel a greater distance as it is the <u>lighter</u> component

Bromobenzene will travel least as it is the <u>heavier</u> component.

thin layer chromatography (TLC) is a type of chromatographic seperation technique that is based on the molecular size of components. the Rf value is the distance covered by the component relative to that travelled by the solvent which is the mobile phase

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An atom of oxygen is in an excited state. When an electron in this atom moves from the third shell to the second shell, energy i
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4 years ago
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Which of the following is the best description of a chemical reaction?
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When you’re substance either starts to smell, smoke, explode, change color. Any of those happening are proof of a chemical reaction.
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3 years ago
The use of uranium-238 to determine the age of a geological formation is a beneficial use of
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3 0
3 years ago
*finished the test its B* In a science lab, a student heats up a chemical from 10 °C to 25 °C which requires thermal energy of 3
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Answer:

Yup! The answer is 50 J/g* °C

Explanation:

I also took the test but I know how to work out the problem for anyone who wants to know how to solve it.

Remember the formula q = m*C*ΔT

m = the mass in grams

C = the specific heat Capacity

ΔT = change in time

q = amount of energy

So, find out what was given and what we need to look for:

m = 40 g

C = ?

ΔT = we're heating up (the temperature increases) a chemical so it needs to be a positive number. 25 - 10 = 15 °C

q = 30000 Joules

Now, set up the equation:

q = m*C*ΔT

30000 = 40 * C * 15

Multiply 40 and 15 to get 600:

30000 = 600 * C

Divide both sides by 600 to get C by itself (plug this into your calculator):

30000/600 = 600 * C/600

You are left with 50 = C

Now, you just need to plug in the units to get B. 50 J/g* °C

I hope I helped clear up any confusion! :D

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