That would be the belief that there is more than one god.
Answer:
Explanation:
Given data:
A) Moles of H₂O₂ = 7.00
Mass of H₂O₂ = ?
Solution:
Number of moles = mass/ molar mass
Now we will rearrange this formula:
Mass = Number of moles × molar mass
Mass = 7.00 mol × 34 g/mol
Mass = 238 g
B) Moles of NaOH = 5.60 mol
Mass of NaOH = ?
Solution:
Number of moles = mass/ molar mass
Now we will rearrange this formula:
Mass = Number of moles × molar mass
Mass = 5.60 mol × 40 g/mol
Mass = 224 g
C) Moles of Ca(CN)₂ = 0.780
Mass of Ca(CN)₂ = ?
Solution:
Number of moles = mass/ molar mass
Now we will rearrange this formula:
Mass = Number of moles × molar mass
Mass = 0.780 mol × 92.11 g/mol
Mass = 71.85 g
Balanced equation will be as follows
2NaOH + H2SO4=Na2SO4 + 2H2O
from MaVa/MbVb=Na/Nb where Ma is molarity of acid=?
Va is volume of acid=25.0 mL
Mb is molarity of base= 0.05 M
Vb is volume of base=18.3 mL
Nb number of moles of base= 2
Na is number of moles of acid =1
Ma*25 mL / 18.3mL*0.05M = 1/2
Ma=18.3*0.05M / 50 = 0.0183M
The molarity of sulphuric acid = 0.0183M
Answer:
Mass = 80.6 g
Explanation:
Given data:
Mass of N₂ consumed = ?
Mass of CaCN₂ formed = 265 g
Solution:
Chemical equation:
CaC₂ + N₂ → CaCN₂ + C
Number of moles of CaCN₂:
Number of moles = mass/molar mass
Number of moles = 265 g/ 92.11 g/mol
Number of moles = 2.88 mol
Now we will compare the moles of CaCN₂ and N₂.
CaCN₂ : N₂
1 : 1
2.88 : 2.88
Mass of N₂:
Mass = number of moles × molar mass
Mass = 2.88 mol × 28 g/mol
Mass = 80.6 g
Answer:
c. Cr
Explanation:
The compound is containing ion.
If acid reacts with it, CO_2 evolves.
therefore, Cr would form a precipitate when added to an aqueous solution of this compound. Cr2CO3 is the precipitate.