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3 years ago

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Chemistry

1 answer:

love history [14]3 years ago

5 0

Answer:

Ans => C => 43.3%

Explanation:

2CO + O₂ => 2CO₂

Given 1g CO = 1g/28g·mol⁻¹ = 0.036 mol CO

b/c coefficient of CO = coefficient of CO₂ => moles CO₂ = 0.036 mol = 0.036mol x 44g/mol = 1.57 gCO₂ (theoretical yield)

%Yield = (actual yield/theoretical yield) x 100% = (0.68g/1.57g) x 100% = 43.3%

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Based on the position of the elements in the periodic table, what is the charge of the ions they are most likely to form?

Rainbow [258]

Explanation:

The charge on an ion denotes the amount of electrons lost or gained or even shared by an atom.

An atom will lose, gain or share an equal amount of electrons that will make it stable and achieve an octet and perfect configuration.

This is often synonymous with the component number of electrons in their outermost shell. The valence shell.

For metals on the periodic table, they are always willing to give up electrons due to their large electropositivity.

Metals will give up the number of electrons in their outermost shell to become stable.

Groups 1 and Group 2 will have charges +1 and +2 on them.

For non-metals , they will gain the exact number of electrons that will make them stable. We must note that half -filled and fully filled orbitals are equally stable.

Elements in groups 6 and 7 are electronegative and will have a charge of -2 and -1 respectively.

For those in groups 3, 4 and 5 they either gain, lose or share commensurate amount of electrons that will make them stable.

Group 8 elements are stable and have no charges.

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3 years ago

The least massive of all the alkaline earth metals. Who am I?

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Answer:argon

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3 years ago

What graph would you use if you wanted to compare similar data for several individual items or events?

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1 year ago

Read 2 more answers

What is the conjugate acid of HCO3- ?OH-H2CO3CO32-H2OH3O+

adell [148]

Answer: The conjugate acid of $HCO_3^-$ is $H_2CO_3$

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory:

An acid is defined as a substance which looses donates protons and thus forming conjugate base.
A base is defined as a substance which accepts protons and thus forming conjugate acid.

To form a conjugate acid of $HCO_3^-$ , this compound will accept one proton to form $H_2CO_3$

The chemical equation for the formation of conjugate acid follows:

$HCO_3^-+H^+\rightarrow H_2CO_3$

The conjugate acid formed is named as carbonic acid.

Hence, the conjugate acid of $HCO_3^-$ is $H_2CO_3$

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3 years ago

A mixture of MgCl2 and NaCl has an initial mass of 0.4015 g. Excess AgNO3(aq) was added and 1.032 g of precipitate, AgCl(s), was

zlopas [31]

Answer:

8.909*10^-4 moles

Explanation:

The mixture contains MgCl $_{2}$ and NaCl with a total mass of 0.4015 g. The mass of precipitate AgCl(aq) is 1.032 g and it has a molar mass of 143.32 g/mol. Therefore, the moles of the precipitate is:

n = 1.032/143.32 = 7.2007*10^-3 moles

Molar mass of NaCl = 58.44 g/mol and the molar mass of MgCl $_{2}$ is 95.21 g/mol. Let the mass (g) of MgCl $_{2}$ in the original mixture be 'x'. Thus:

7.2007*10^-3 = (0.4015-x)/58.44 + 2x/95.21

(7.2007*10^-3)*58.44*95.21 = 95.21(0.4015-x) + 2x(58.44)

40.06505 = 38.227 -95.21x + 116.88x

40.06505 - 38.227 = -95.21x + 116.88x

1.83805 = 21.67x

x = 1.83805/21.67 = 0.0848 g

moles of MgCl $_{2}$ = 0.0848g/95.21 g/mol = 8.909*10^-4 moles

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3 years ago