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Dmitry [639]
3 years ago
5

You have three drinks in front of you. you know how they are made, but are unsure which one has the highest concentration of jui

ce crystals. The first drink has 10g of juice crystals dissolved in 50mL of water. The second drink has 15g of juice crystals dissolve in 100 mL of water and the third drink has 6g of juice crystals dissolve in 25 ml of water.
make a plan to figure out the concentration of each drink. what was the most concentrated drink? How did you determine this since all three drinks had different amounts of solvent?
Chemistry
2 answers:
NikAS [45]3 years ago
5 0

Answer:

Explanation:

i think the last one is correct

GuDViN [60]3 years ago
4 0

(I think) you would have to divided the number i dont know the exact answer but ya hope this help
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an engineer wishes to design a container that will hold 12.0 mol of ethane at a pressure no greater than 5.00x10*2 kPa and a tem
OleMash [197]

Answer:

The minimum volume of the container is 0.0649 cubic meters, which is the same as 64.9 liters.

Explanation:

Assume that ethane behaves as an ideal gas under these conditions.

By the ideal gas law,

P\cdot V = n\cdot R\cdot T,

\displaystyle V = \frac{n\cdot R\cdot T}{P}.

where

  • P is the pressure of the gas,
  • V is the volume of the gas,
  • n is the number of moles of particles in this gas,
  • R is the ideal gas constant, and
  • T is the absolute temperature of the gas (in degrees Kelvins.)

The numerical value of R will be 8.314 if P, V, and T are in SI units. Convert these values to SI units:

  • P =\rm 5.00\times 10^{2}\;kPa = 5.00\times 10^{2}\times 10^{3}\; Pa = 5.00\times 10^{5}\; Pa;
  • V shall be in cubic meters, \rm m^{3};
  • T = \rm 52.0 \textdegree C = (52.0 + 273.15)\; K = 325.15\; K.

Apply the ideal gas law:

\displaystyle \begin{aligned}V &= \frac{n\cdot R\cdot T}{P}\\ &= \frac{12.0\times 8.314\times 325.15}{5.00\times 10^{5}}\\ &= \rm 0.0649\; m^{3} \\ &= \rm (0.0649\times 10^{3})\; L \\ &=\rm 64.9\; L\end{aligned}.

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