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Vesnalui [34]
3 years ago
10

Which is the best reason for choosing the beaker for heating the solution?

Chemistry
1 answer:
Luba_88 [7]3 years ago
7 0

It will not tip over a hot plate

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Name the planet: Until recently, this stormy, blue-colored planet had a great dark spot on it, which was a high pressure cyclone
Mnenie [13.5K]
It’s Neptune hehe :))
4 0
3 years ago
Read 2 more answers
If 40.0 g of water at 70.0°c is mixed with 40.0 g of ethanol at 10.0°c, what is the final temperature of the mixture?
FinnZ [79.3K]
When the heat lost by water = heat gained by ethanol

∴(  M* C * ΔT )w  = (M*C*ΔT ) eth

when Mw mass of water = 40 g 

C specific heat of water = 4.18

ΔT = (70- Tf) 

and M(eth) mass (ethanol) = 40 g 

C specific heat of ethanol = 2.44 

ΔT = (Tf - 10 ) 

by substitution:

40* 4.18 * (70 - Tf) = 40 * 2.44 * (Tf-10) 

∴Tf = 47.9 °C 
3 0
4 years ago
3
Bess [88]

Answer:

4Al + 3O₂ →   2Al₂O₃

Explanation:

    4Al + 3O₂ →   2Al₂O₃

Only this reaction above obeys the law of conservation of mass. The others flout the rule.

The law of conservation of mass states that "matter is neither created nor destroyed in a chemical reaction but are simply transformed from one form to another".

By this law, the number of atoms on both sides of expression must be the same;

                                                    Number of atoms

Elements              Left hand side                                 Right hand side

  Al                                    4                                                     4

  O                                    6                                                    6

8 0
3 years ago
How many liters of chlorine are needed to produce 5.64 moles of aluminum chloride? Need help ASAP
Romashka-Z-Leto [24]

Answer:

190 L

Explanation:

Given that:

Number of moles = mass/molar mass

number of moles = 5.64

molar mass of aluminum chloride = 133.34 g/mol

∴

The balanced equation is:

2 Al + 3 Cl2 --> 2AlCl3.

From above reaction:

5.64 mole of  AlCl3 reacts with 3 mole Cl2  to give 2 mole AlCl3

i.e

(5.64 \ mole \  AlCl3) \times  (3  \ mole  \ Cl2  \ / \ 2 \  mole \  AlCl3)

= 8.46 mole Cl2 gas.

At Standard temperature and pressure:

= (22.4 L/1 mole gas) * (8.46 mole Cl2)

= 190 L chlorine gas

7 0
3 years ago
If the partial molar volumes of the two components of a binary solution are VA 30 m2/mol and Vg 20 m3/mol and the mole fraction
gregori [183]

Answer : The molar volume of the solution is, 24m^3/mole

Explanation : Given,

Partial molar volumes of component A = 30m^3/mole

Partial molar volumes of component B = 20m^3/mole

Mole fraction of component A = 0.4

First we have to calculate the mole fraction of component B.

As we know that,

\text{Mole fraction of component A}+\text{Mole fraction of component B}=1

\text{Mole fraction of component B}=1-0.4=0.6

Now we have to calculate the molar volume of the solution.

Expression used :

V_s=X_A\times \bar V_A+X_B\times \bar V_B

where,

\bar V_A = partial molar volumes of component A

\bar V_B = partial molar volumes of component B

V_s =  molar volume of the solution

X_A = mole fraction of of component A

X_B = mole fraction of of component B

Now put all the give values in the above expression, we get:

V_s=0.4\times 30m^3/mole+0.6\times 20m^3/mole

V_s=24m^3/mole

Therefore, the molar volume of the solution is, 24m^3/mole

3 0
3 years ago
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