The answer is d I believe
Answer:
In order to attain stability
Explanation:
Every chemical bonds that are formed results from the desires of atoms to achieve stability like the inert and nonreactive noble gases. By so doing, their outer shell electrons must be completely filled to attain an octet configuration like the noble gases with eight outermost electrons.
An atom of oxygen has six outer electrons. To complete its octet, it will require just two more electrons.
This desire will make it bond with another atom. In the vicinity of another oxygen atom, it will bond. The type of bond formed will be a covalent bond which results from each of the oxygen atom sharing two of their valence electrons.
The joint shared electrons will now be four electrons. This four electrons will make each of their octet complete and a covalent bond occurs.
If they are in the same group they have the same valence electrons but since I cannot see what you’re talking about I’m not sure what your question is
Answer:
a) MZ₂
b) They have the same concentration
c) 4x10⁻⁴ mol/L
Explanation:
a) The solubility (S) is the concentration of the salt that will be dissociated and form the ions in the solution, the solubility product constant (Kps) is the multiplication of the concentration of the ions elevated at their coefficients. The concentration of the ions depends on the stoichiometry and will be equivalent to S.
The salts solubilization reactions and their Kps values are:
MA(s) ⇄ M⁺²(aq) + A⁻²(aq) Kps = S*S = S²
MZ₂(aq) ⇄ M⁺²(aq) + 2Z⁻(aq) Kps = S*S² = S³
Thus, the Kps of MZ₂ has a larger value.
b) A saturated solution is a solution that has the maximum amount of salt dissolved, so, the concentration dissolved is solubility. As we can notice from the reactions, the concentration of M⁺² is the same for both salts.
c) The equilibrium will be not modified because the salts have the same solubility. So, let's suppose that the volume of each one is 1 L, so the number of moles of the cation in each one is 4x10⁻⁴ mol. The total number of moles is 8x10⁻⁴ mol, and the concentration is:
8x10⁻⁴ mol/2 L = 4x10⁻⁴ mol/L.