Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
<span> 5*(x-2)-4*(x+1)-(50)=0 </span>
Let 4 + 3x = u
then 3dx = du
or, <span>1/3∫<span>u√</span>du
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= <span>1/3<span>u^<span>3/2</span></span>/(3/2)
</span>
= <span>2/9∗(4+3x<span>)^<span>3/2
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I think it’s A but I’m not to sure
1 dozen = 12
Divide 941 by 12:
941 / 12 = 78.42
So the greatest number of dozens he can make is 78.
Answer:
A
Step-by-step explanation:
