1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
REY [17]
3 years ago
11

How are particles held together in each phase of matter

Chemistry
1 answer:
Ainat [17]3 years ago
4 0
Particles in solids are held together very closely.

This makes them very strong and difficult to break apart. Solids can also hold their own shape

The particles don’t move around very much but simply vibrate in their spot.

Particles in liquids are quite close to each other, however they can move past each other very easily.

This makes liquids very easy to break apart and why they cannot hold their own shape, but instead take the shape of their container

The particles in liquids move around quite a bit, bumping gently past each other.

Particles in gases move around very quickly with a lot of space between them, this means you can compress them very easily.

Gases don’t just take the shape of their container they fill the space of the container that they are in

You might be interested in
For each set of values, calculate the missing variable using the ideal gas law.
allsm [11]

Answer:

1. n = 0.174mol

2. T= 26.8K

3. P = 1.02atm

4. V = 126.88L

Explanation:

1. P= 2.61atm

V = 1.69L

T = 36.1 °C = 36.1 + 273= 309.1K

R = 0.082atm.L/mol /K

n =?

n = PV / RT = (2.61x1.69)/(0.082x309.1)

n = 0.174mol

2. P = 302 kPa = 302000Pa

101325Pa = 1atm

302000Pa = 302000/101325 = 2.98atm

V = 2382 mL = 2.382L

T =?

n = 3.23 mol

R = 0.082atm.L/mol /K

T= PV /nR = (2.98x2.382)/(3.23x0.082) = 26.8K

3. P =?

V = 0.0250 m³ = 25L

T = 288K

n = 1.08mol

R = 0.082atm.L/mol /K

P = nRT/V = (1.08x0.082x288)/25 = 1.02atm

4. P = 782 torr

760Torr = 1 atm

782 torr = 782/760 = 1.03atm

V =?

T = 303K

n = 5.26 mol

R = 0.082atm.L/mol /K

V = nRT/P

V = (5.26x0.082x303)/1.03 = 126.88L

8 0
4 years ago
Which mass of urea, CO(NH2)2, contains the same mass of nitrogen as 101.1g of potassium nitrate?
Effectus [21]
In order to calculate the mass of nitrogen, we must first calculate the mass percentage of nitrogen in potassium nitrate. This is:
% nitrogen = mass of nitrogen / mass of potassium nitrate
% nitrogen = 14 / 101.1 x 100

The mass of nitrogen = % nitrogen x sample mass
= (14 / 101.1) x 101.1
= 14 grams

The molar weight of nitrogen is 14. Each mole of urea contains two moles of nitrogen. Therefore, for there to be 14 grams of nitrogen, there must be 0.5 moles of urea.
Mass of urea = moles urea x molecular weight urea
Mass of urea = 0.5 x 66.06
Mass of urea = 33.03 grams
4 0
3 years ago
What is the volume occupied by 30.00 grams of pure gold?​
mr Goodwill [35]

Answer:

I think 1.56

Explanation:

3 0
3 years ago
. Which law of motion relates the action of a stretched rubber band
storchak [24]

Answer:

newtons 3rd law of motion

Explanation:

3 0
3 years ago
H2 + O2 ----> H2O What is the mole ratio of hydrogen to water?
notsponge [240]

2:2

ioudhfihsOIUDHFIUOSAHD

8 0
3 years ago
Read 2 more answers
Other questions:
  • The following observations are made about two hypothetical elements A and B: The A?A and B?Bbond lengths in elemental A and B ar
    6·1 answer
  • Which of the following is a homogeneous mixture?
    7·2 answers
  • What is the mass, in grams, of 7.20×1020 molecules of caffeine, c8h10n4o2?
    11·2 answers
  • If a buffer contains 1.05M B and 0.750M BH+ has the pH of 9.5. What would be the pH after 0.005mol of HCL is added to 0.5L of so
    8·1 answer
  • Yo answer my question
    13·2 answers
  • Can someone please help me
    6·1 answer
  • Help ASAP I will mark brainliest to he correct answer
    7·1 answer
  • Is the equation 2NO+02 NO, balanced? Explain your answer
    15·1 answer
  • You plan to use the water displacement method to
    13·1 answer
  • How
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!