Answer:
grams H₂O produced = 8.7 grams
Explanation:
Given 2C₂H₆(g) + 7O₂(g) => 4CO₂(g) + 6H₂O(l)
7g 18g ?g
Plan => Convert gms to moles => determine Limiting reactant => solve for moles water => convert moles water to grams water
Moles Reactants
moles C₂H₆ = 7g/30g/mol = 0.233mol
moles O₂ = 18g/32g/mol = 0.563mol
Limiting Reactant => (Test for Limiting Reactant) Divide mole value by respective coefficient of balanced equation; the smaller number is the limiting reactant.
moles C₂H₆/2 = 0.233/2 = 0.12
moles O₂/7 = 0.08
<u><em>Limiting Reactant is O₂</em></u>
Moles and Grams of H₂O:
Use Limiting Reactant moles (not division value) to calculate moles of H₂O.
moles H₂O = 6/7(moles O₂) = 6/7(0.562) moles H₂O = 0.482 mole H₂O yield
grams H₂O = (0.482mol)(18g·mol⁻¹) = 8.7 grams H₂O
The dependant variable is what you measure during the experiment and what is affected in the experiment (this is for question 4) so the answer would be D
Answer:
The temperature is 288, 88K
Explanation:
We use the formula PV= nRT:
T= PV/nR
T= 0,987 atm x12 L/0,50 mol x 0,082 l atm/K mol
<em>T=288,88K</em>
Answer:
Milk, cream, milk solids, sugars, modifying agents and flavourings are blended together in stainless steel vats.
The mix is homogenised to create a consistent texture.
The mix is pasteurised by heating at 82-85°C for 15 seconds then cooled to destroy bacteria.
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