Explanation:
Nuclear fusion produces more energy with less radioactive waste compared to nuclear fission process.
- In nuclear fission, a radioactive decay occurs in which a heavy nucleus spontaneously disintegrates into two lighter nuclei and several neutrons with the release of energy.
- Nuclear fusion occurs when small atomic nuclei combines into larger ones with the release of a large amount of energy.
- Instability of a nuclide is enough to start up a nuclear fission reaction. In some instances, a heavy nuclide is bombarded with another nuclide.
- In nuclear fusion, the activation energy required to start up is very great.
Nuclear wastes emanating from nuclear fusion process is least compared to that of nuclear fission.
Nuclear fusion produces more energy compared to nuclear fission process.
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Answer:The molar mass of a compound cab be find by adding up all the molar mass of the element present in the compound... Check the image for more clarification
Explanation:
The ml is also called as the magnetic quantum number. The value
of ml can range from –l to +l including zero. Hence all of the possible values for ml given
that l = 2 are:
<span>-2, -1, 0, + 1, + 2</span>
Answer: B. It’s a dilute strong base.
Explanation:
1) Definition of acids and bases: as per Bronsted-Lowry model, an acid is a substance that donates hydrogen ions and a base is a substance that accepts hydrogen ions.
Ca(OH)₂ does not have hydrogen ions to donate, but it can accept hydrogen ions to form H₂O according to this equation: H⁺ + OH⁻ → H₂O.
Hence, Ca(OH)₂ is a base.
2) Definition of strong base: a strong base is a base that dissociates completely into metallic and hydroxide ions in aqueous solutions, while a weak base dissociates partially.
Hence, Ca(OH)₂ is a strong base.
3) Definition of dilute: it refers to a solution meaning that the substance is not pure and the concentration is low. Since, the solution the Ca(OH)₂ is 0.02 M means that it is dilute.
Therefore, we have found that the description of 0.02 M Ca(OH)₂ is that is is a dilute strong base (option B).
To Tell how much of each reactant will be used in a reaction, we need to find which reactant is the Limiting Reagent.
All the reactants will be consumed in equal amount as that of L.R.
