Answer:
In an ionic bonds, the metal loses electrons to become a positively charged cation, In which the nonmetal accepts those electrons to become a negatively charged anion.
Explanation:
Answer: The empirical formula is .
Explanation:
If percentage are given then we are taking total mass is 100 grams.
So, the mass of each element is equal to the percentage given.
Mass of C = 50.69 g
Mass of N= 19.71 g
Mass of H = 7.09 g
Mass of O = 22.51 g
Step 1 : convert given masses into moles.
Moles of C =
Moles of N=
Moles of H=
Moles of O =
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C =
For N =
For H =
For O =
The ratio of C:N:H: O = 3:1:5:1
Hence the empirical formula is .
Answer:
Mass FeCl2 = 0.0333g
Mass CrCl2 = 0.9961g
Explanation:
To solve this problem. The first equation we can write is:
Mass FeCl2 + Mass CrCl2 = 1.0294g <em>(1)</em>
Now, the Chlorides of FeCl2 and CrCl2 react producing 2.3609g of AgCl
Using molar mass of these species (126.75g/mol, 122.9g/mol, 143.32g/mol, respectively), you can write the equation:
2Mass FeCl2 / 126.75 + 2Mass CrCl2 / 122.9 = 2.3609/143.32
<em>That is: Moles Chloride before = Moles Chloride in AgCl after reaction</em>
7.8895x10⁻³Mass FeCl2 + 0.0162734MassCrCl2 = 0.016473 <em>(2)</em>
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Replacing (1) in (2):
7.8895x10⁻³ (1.0294g - MassCrCl2) + 0.0162734MassCrCl2 = 0.016473
8.12145x10⁻³ -7.8895x10⁻³MassCrCl2 + 0.0162734Mass CrCl2 = 0.016473
8.3839x10⁻³ MassCrCl2 = 8.35155x10⁻³
Mass CrCl2 = 0.9961g
And:
Mass FeCl2 = 1.0294g - 0.9961g
Mass FeCl2 = 0.0333g
The answer to this question would be: <span>B. They have a higher mass
The mass of an atom is determined by their mass number which was the sum of their protons and neutrons. Protons of an element will be same. So any isotope of an element will have the same number of proton, no isotope should have more proton. The mass is increased because some isotope has more neutrons than others, resulting in a higher mass.</span>