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kirill [66]
3 years ago
7

Particle quantity/number of Cu(NO3)2

Chemistry
1 answer:
Murrr4er [49]3 years ago
8 0

Answer:

Cupid nitrate is what I'm going for

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N2O4(g) + 4H2(g) → N2(g) + 4H2O(g), solve using standard enthalpies of formation
aev [14]

The standard enthalpy of formation (ΔH_f) is a measure of the energy released or consumed when one mole of a substance is created under standard conditions from its pure elements.

Standard enthalpies (ΔH_f) of formation for given reaction is 978.3 kJ

<h3>What is Standard enthalpies of formation?</h3>

The standard enthalpy of formation is defined as the enthalpy change when one mole of a substance in the standard state (1 atm of pressure and 298.15 K) is formed from its pure elements under the same conditions.

Given reaction ;

N_2O_4(g) + 4H_2 (g) - > N_2(g) + 4H_2O(g)

To Find : ΔH_f

ΔH_f = ∑np ΔH_f (products) – ∑np ΔH_f (reactants)

ΔH_f = [1(ΔH_f N_2) + 4(ΔH_f H_2O)] – [1(ΔH_f N_2O_4) + 4(ΔH_f H_2)]

ΔH_f = [1(0) + 4(-241.8)] – [1(+9.16) + 4(0)]

ΔH_f  = [4(-241.8)] – [1(+9.16)] = 978.3 kJ

Learn more about Enthalpy here ;
brainly.com/question/16720480

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