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Monica [59]
3 years ago
10

Which of the following statements are FALSE of models? (select all that applies)

Chemistry
1 answer:
ira [324]3 years ago
7 0

Answer:

A B and C

Explanation:

Hopefully this helps

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A sample of gas has a volume of 4.4 liters when the pressure is 3.3atm. What is the volume when the pressure is reduced to 2.2at
oee [108]
You'll remain with 2.9 liter
4 0
3 years ago
What do all viruses have in common? Choose more than one answer.
vitfil [10]

Answer:

1, 3, 4, and 5

Explanation:

the number would be the dot order!

7 0
3 years ago
Is energy transfer the process by which any form of energy changes location?
Elis [28]
Yes, transfer of energy is known as an energy transfer
4 0
3 years ago
What is the volume, in liters, of 6.8 mol of Kr gas at STP?
Virty [35]

Answer:

\boxed {\boxed {\sf D. \ 152 \ L}}

Explanation:

Any gas at standard temperature and pressure (STP) has a volume of 22.4 liters per mole or 22.4 L/mol. We can create a proportion with this value.

\frac {22.4 \ L \ Kr}{1 \ mol \ Kr}

Multiply both sides of the equation by 6.8 moles of krypton.

6.8 \ mol \ Kr *\frac {22.4 \ L \ Kr}{1 \ mol \ Kr}

The units of moles of krypton will cancel.

6.8 *\frac {22.4 \ L \ Kr}{1 }

The denominator of 1 can be ignored, so this becomes a simple multiplication problem.

68 * 22.4 \ L \ Kr

152.32 \ L \ Kr

If we round to the nearest whole number, the 3 in the tenths place tells us to leave the 2 in the ones place.

152 \ L \ Kr

6.8 moles of krypton gas at standard temperature and pressure is equal to <u>152 liters</u>.

6 0
3 years ago
How would you prepare 1.00 L of a 0.50 M solution of each of the following?
Lunna [17]

Answer:

Take approx 41.7 mL of 12-M HCl in a 1.00-L flask and fill the rest of the volume with distilled water.

Explanation:

Hello,

In this case, for the dilution process from concentrated  12-M hydrochloric acid to 1.00 L of the diluted 0.50M hydrochloric acid, the volume of concentrated HCl you must take is computed by considering that the moles remain constant for all dilution processes as shown below:

n_1=n_2

Which can also be written in terms of concentrations and volumes:

M_1V_1=M_2V_2

Thus, solving for the initial volume or aliquot that must be taken from the 12-M HCl, we obtain:

V_1=\frac{M_2V_2}{M_1} \\\\V_1=\frac{1.00L*0.5M}{12M}\\ \\V_1=0.0417L=41.7mL

It means that you must take approx 41.7 mL of 12-M HCl in a 1.00-L flask and fill the rest of the volume with distilled water for such preparation.

Best regards.

6 0
3 years ago
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