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disa [49]
3 years ago
6

1. identify whether following have ionic or covalent bonding. Give your reasons: Oxygen molecule, water, calcium oxide, hydrogen

oxide, sodium chloride, hydrogen chloride, magnesium fluoride, ammonia, sulphur dioxide
2. Make a table, and list all properties of ionic compounds and covalent compounds in different columns.
Chemistry
1 answer:
Romashka [77]3 years ago
5 0
First you need to know the different between an ionic and covalent bond. An ionic bond is the pairing of a metal and non-metal element. A covalent bond is the pairing of 2 nonmetals.

Metals are the elements at the left of the periodic table while non-metals are the elements at the right of the periodic table.

You should also know the diatomic (di means 2) molecules also known as the fab 7. These molecules will always form covalent bonds. These molecules are hydrogen, nitrogen, oxygen, fluorine, chlorine, bromine, and iodine. With the subscripts, these molecules would be written as H ₂, N ₂, O ₂, F ₂, Cl ₂, Br ₂, and I ₂.
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How many moles are contained in 70. milliliters of a 0.167 M solution of p-toluidine hydrochloride? Enter only the number to two
kramer

<u>Answer:</u> The amount of p-toluidine hydrochloride contained is 2.4 moles.

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}

Molarity of p-toluidine hydrochloride solution = 0.167 M

Volume of solution = 70. mL

Putting values in equation 1, we get:

0.167=\frac{\text{Moles of p-toluidine hydrochloride}\times 1000}{70}\\\\\text{Moles of p-toluidine hydrochloride}=\frac{(0.167\times 70}{1000}=2.38mol=2.4mol

Hence, the amount of p-toluidine hydrochloride contained is 2.4 moles.

6 0
4 years ago
Determine the change in entropy for 2.7 moles of an ideal gas originally placed in a container with a volume of 4.0 L when the c
olchik [2.2K]

Answer:

The value of entropy change for the process dS = 0.009 \frac{KJ}{K}

Explanation:

Mass of the ideal gas = 0.0027 kilo mol

Initial volume V_{1} = 4 L

Final volume V_{2} = 6 L

Gas constant for this ideal gas ( R ) = R_{u}  M

Where R_{u} = Universal gas constant = 8.314 \frac{KJ}{Kmol K}

⇒ Gas constant R = 8.314 × 0.0027 = 0.0224 \frac{KJ}{K}

Entropy change at constant temperature is given by,

dS = R  log _{e} \frac{V_{2}}{V_{1}}

Put all the values in above formula we get,

dS = 0.0224  log _{e} [\frac{6}{4}]

dS = 0.009 \frac{KJ}{K}

This is the value of entropy change for the process.

6 0
3 years ago
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Answer:

Mixture is the answer.

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4 years ago
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I think it means the reaction doesn't have any intermediate phases - the order doesn't change, and it moves at the same rate, it doesn't speed up or slow down at any time
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