Question

The (OH) of a given solution =1.00x10-9M. what is this solution s pOH?

Answer 1

Answer:

9

Explanation:

Given parameters:

Concentration of OH⁻ [OH]= 1 x 10⁻⁹M

Solution:

To find the pOH of a solution can be found using the expression below:

                   pOH = -log₁₀[OH]

          [OH] = concentration of the hydroxyl ions

       pOH = -log₁₀(1 x 10⁻⁹) = - x -9 = 9

Answer 2

Answer:

The soultion of pOH=9

Explanation:

We can determine the acidity or the basicity of the solution using the pOH value.

The solution is acidic if the pOH value ranges from 7.1 to 14

The solution is Basic if the pOH value ranges from 0 to 6.9  

The solution is neutral if the pOH value is 7.

pOH is defined as the negative logarithm of the Hydroxide ion concentration, that’s why the formula to find pOH is given by  

$pOH=-log[OH^-]$

$pOH=-log[1.00\times10^{-9}M]$

$=-[-9]$

$pOH=9$

(Answer)

Please note :  

A Base is a substance which produces one or more hydroxyl ion or  hydroxide ion (OH-) in aqueous solution.

Examples

$NaOH(s)>Na^+ (aq) + OH^- (aq)\\\\KOH(s)>K^+ (aq) +OH^- (aq)\\\\Ca(OH)_2 (s)>Ca^{2+} (aq) +2OH^{- }(aq)\\\\Al(OH)_3 (s)> Al^{3+} (aq)+ 3OH^- (aq)$

Please note:

(aq) stands for aqueous which means in the presence of water that is,water   acts as a solvent

So, on adding a base to the water increase in $[OH^-]$ will take place and this will decrease the Hydrogen ion concentration  

Pure water contains $[H^+ ]=[OH^- ]$

if the solution is acidic $[H^+ ]>[OH^- ]$

if the solution is Basic $[H^+ ]$