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4 years ago

Is naphthalene non-polar?

1 answer:

3 0

Napthalene, with chemical formula of C10H8, is a non polar compound. It has a dipole moment of zero. Having a planar with D2H symmetry, results to the zero dipole moment which makes it non-polar. Hope this answers the question. Have a nice day.

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What is the balanced equation for H3PO4=H4P2O7+H2O

podryga [215]

Answer:

2H3PO4=H4P2O7+H2O

Explanation:

2H3PO4=H4P2O7+H2O

5 0

3 years ago

Low energy waves have (3 points)

Sergeeva-Olga [200]

Answer:

Low energy waves have <u>a long wavelength.</u>

Explanation:

Energy of wave is directly related to the frequency while it is inversely proportional to the wavelength.

If any wave have high energy it will have high frequency and smaller wavelength.

If the wave have lower energy then it will have lower frequency and higher wavelength.

Mathematical relationship:

E = h. f

E = h. c/λ

E= energy

h = planck's constant

f = frequency

c = speed of light

λ = wavelength

7 0

4 years ago

In addition to not causing damage to the sample, what is another advantage of using a microspectrophotometer to analyze fibers?

Tems11 [23]

Another advantage of advantage of using a microspectrophotometer to analyze fibers asides not causing damage to the sample is that the sample can be quite small.

<h3>What is a microspectrophotometer?</h3>

Microspectrophotometry is a biological technique used to measure the absorption or transmission spectrum of a solid or liquid material in either transmitted or reflected light.

Microspectrophotometry can also measure the emission of light by a sample, which is usually small as the micro implies.

One advantage of microspectrophotometry is that the sample does not get damaged. However,

However, another advantage of advantage of using a microspectrophotometer to analyze fibers asides not causing damage to the sample is that the sample can be quite small.

Learn more about microspectrophotometry at: brainly.com/question/5832827

5 0

2 years ago

What is the number of atoms per unit cell for each metal?

Sav [38]

In the question, the number of atoms per unit cell is required for:
A) Polonium (Po)
In polonium, the structure is simple cubic, meaning there are 8 corner atoms, which add up to one atom per unit cell.

B) Manganese (Mn)
The structure of the Mn can be considered to be a body centered cubic (BCC) and the number of atoms for this is 8 corner atoms and 1 central atoms, making a total of 2 atoms per unit cell.

C) Silver (Ag)
Silver has a face centered cubic (FCC) unit cell structure, where there are 8 corner atoms and 6 atoms on the faces, so there are a total of 4 atoms per unit cell.

4 0

3 years ago

What is the percent yield of CuS for the following reaction given that you start with 15.5 g of Na2S and 12.1 g CuSO4? The actua

notka56 [123]

Answer:

(B) 42.1%

Explanation:

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Given: For $Na_2S$

Given mass = 15.5 g

Molar mass of $Na_2S$ = 78.0452 g/mol

<u>Moles of $Na_2S$ = 15.5 g / 78.0452 g/mol = 0.1986 moles</u>

Given: For $CuSO_4$

Given mass = 12.1 g

Molar mass of $CuSO_4$ = 159.609 g/mol

<u>Moles of $CuSO_4$ = 12.1 g / 159.609 g/mol = 0.0758 moles</u>

According to the given reaction:

$Na_2S+CuSO_4\rightarrow Na_2SO_4+CuS$

1 mole of $Na_2S$ react with 1 mole of $CuSO_4$

0.1986 mole of $Na_2S$ react with 0.1986 mole of $CuSO_4$

Available moles of $CuSO_4$ = 0.0758 moles

Limiting reagent is the one which is present in small amount. Thus, $CuSO_4$ is limiting reagent. (0.0758 < 0.1986)

The formation of the product is governed by the limiting reagent. So,

1 mole of $CuSO_4$ gives 1 mole of $CuS$

0.0758 mole of $CuSO_4$ gives 0.0758 mole of $CuS$

Molar mass of $CuS$ = 95.611 g/mol

Mass of $CuS$ = Moles × Molar mass = 0.0758 × 95.611 g = 7.2473 g

Theoretical yield = 7.2473 g

Given experimental yield = 3.05 g

% yield = (Experimental yield / Theoretical yield) × 100 = (3.05/7.2473) × 100 = 42.1 %

<u>Option B is correct.</u>

6 0

3 years ago