he interaction between a baseball bat and a baseball
Answer:
(a) 1 atm, 8.72 L and 298 K respectively.
(b) 1 atm, 16.72 L and 573.35 K respectively.
(c) 
Explanation:
Hello,
(a) In this case, considering that neon could be considered as an ideal gas, we can compute its volume as follows:
Thus, initial conditions of pressure volume and temperature are 1 atm, 8.72 L and 298 K respectively.
(b) Since the process was carried out at constant pressure, the work is defined as:
Thus, the final volume is:
And the final temperature is computed by considering the pressure-constant specific heat of neon (1.03 J/g*K) and the added heat:
Therefore, final volume is 16.72 L, final pressure is also 1 atm and final temperature is 573.35 K for this expansion process.
(c) Finally, the change in the internal energy is computed via the first law of thermodynamics:
Best regards.
Answer:
a. Expansion: the spatial dilation of a material that occurs upon changes in its composition. (an increase in number or amount to become larger in size.)
E.g- in a thermometer, when it gets hotter, the liquid inside them expands and rises up the tube.
b. Sublimation: the process in which a solid changes directly into a liquid.
E.g- dry ice, solid iodine and ammonium salts.
when the above solids are heated, only particles which are found on the surface of the solid have enough energy to break all forces of attraction and form a gas.
c. Contraction: it is the opposite of expansion. when a liquid is cooled the particles slow down and contract.
E.g- when a thermometer is taken out of your mouth, it contracts and the liquid inside falls back to the bottom.
f. Random Motion: motion in which the particle moves in a zig-zag manner and not in a straight line. The kinetic particle theory states that matter is made up of particles which are in constant <em>random motion,</em>
Explanation:
Answer:
Percent by mass of water is 56%
Explanation:
First of all calculate the mass of hydrated compound as,
Mass of Sodium = Na × 2 = 22.99 × 1 = 45.98 g
Mass of Sulfur = S × 1 = 32.06 × 1 = 32.06 g
Mass of Oxygen = O × 14 = 16 × 14 = 224 g
Mass of Hydrogen = H × 20 = 1.01 × 20 = 20.2 g
Mass of Na₂S0₄.10H₂O = 322.24 g
Secondly, calculate mass of water present in hydrated compound. For this one should look for the coefficient present before H₂O in molecular formula of hydrated compound. In this case the coefficient is 10, so the mass of water is...
Mass of water = 10 × 18.02
Mass of water = 180.2 g
Now, we will apply following formula to find percent of water in hydrated compound,
%H₂O = Mass of H₂O / Mass of Hydrated Compound × 100
Putting values,
%H₂O = 180.2 g / 322.24 g × 100
%H₂O = 55.92 % ≈ 56%
Answer: 60 grams
Explanation: (60 ml)*(1g/ml) = 60g
