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zubka84 [21]
3 years ago
9

If the volume and Kelvin temperature are reduced by one-half what will happen to the pressure???

Chemistry
1 answer:
jolli1 [7]3 years ago
6 0

Answer:

the pressure will decrease

Explanation:

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Task B: Use the following maps to complete the questions:
Oksana_A [137]

Answer:

<h3>1. B</h3><h3>2. A</h3><h3>3. B</h3><h3>4. B</h3><h3>5. C</h3><h3>I HOPE IT HELPS :) 100% sureness</h3>
4 0
2 years ago
Read the given expression. X = number of protons − number of core electrons Which of the following explains the identity of X an
shepuryov [24]

<u>Answer: </u>The correct statement is X is the effective nuclear charge, and it increases across a period.

<u>Explanation:</u>

We are given that:

X = number of protons − number of core electrons

Effective nuclear charge is defined as the actual nuclear charge (Z = number of protons) minus the screening effect caused by the electrons present between nucleus and valence electrons. These electrons are the core electrons.

The formula used for the calculation of effective nuclear charge given by Slater is:

Z^*=Z-\sigma

where,

Z^* = effective nuclear charge

Z = atomic number or actual nuclear charge or number of protons

\sigma = Screening constant

The effective nuclear charge increases as we go from left to right in a period because nuclear charge increases with no effective increase in screening constant.

Hence, the correct answer is X is the effective nuclear charge, and it increases across a period.

5 0
3 years ago
A method used by the U.S. Environmental Protection Agency (EPA) for determining the concentration of ozone in air is to pass the
baherus [9]

Answer: 1. 9.08\times 10^{-6} moles

2. 90 mg

Explanation:

O_3(g)+2NaI(aq)+H_2O(l) \rightarrow O_2(g)+I_2(s)+2NaOH(aq)

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus 4.54 \times 10^{-6} moles of ozone is removed by =\frac{2}{1}\times 4.54 \times 10^{-6}=9.08\times 10^{-6} moles of sodium iodide.

Thus 9.08\times 10^{-6} moles of sodium iodide are needed to remove 4.54\times 10^{-6} moles of O_3

2. \text{Number of moles of ozone}=\frac{0.01331g}{48g/mol}=0.0003moles

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus 0.0003 moles of ozone is removed by =\frac{2}{1}\times 0.0003=0.0006 moles of sodium iodide.

Mass of sodium iodide= moles\times {\text {molar mass}}=0.0006\times 150g/mol=0.09g=90mg    (1g=1000mg)

Thus 90 mg of sodium iodide are needed to remove 13.31 mg of O_3.

3 0
2 years ago
Pls help need it now as I don't know the answer
ioda

Answer:

Iron :)))))))))))))))))))))))))

3 0
2 years ago
Read 2 more answers
2. What is the difference between an element and a compound?​
melamori03 [73]

Answer:

element.

.it is pure substance composed of only one type of atoms.

.the number of element is more than 118.

compound.

.a compound is composed of atoms of two or more elements.

.the number of compound is very large in comparison of elements.

hope it help

6 0
2 years ago
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