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svetoff [14.1K]
4 years ago
8

Express 16/2^1/2 as a power of 2

Mathematics
2 answers:
Grace [21]4 years ago
7 0

( \frac{16}{2} )^{ \frac{1}{2} }  = 2 {}^{x}
And if we know

16 \div 2 = 8
So that means

{8}^{ \frac{1}{2} }  =  {2}^{x}
We also know that
2 \times 2 \times 2 = 8
Which is equivalent to
{2}^{3}  = 8
So if we rewrite the equation with this...
2 {}^{3 \times  \frac{1}{2} }  =  {2}^{x}
So that means

3 \times  \frac{1}{2}  = x
x =  \frac{3}{2}
And we get to the end result that

( \frac{16}{2} ) {}^{ \frac{1}{2} }  = 2 {}^{ \frac{3}{2} }
boyakko [2]4 years ago
7 0

Question

Express 16/2^1/2 as a power of 2


Answer:

<h2> 2² </h2>

Step-by-step explanation:

16/2^1/2 =

8/2 =

4

4 = 2²

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Stella [2.4K]
Your sequence appears to be geometric with a common ratio of 2. It can be described by
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_____
This can be written in a number of other forms, including
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4 years ago
7th grade math help me plzzzz
Montano1993 [528]
A. 6 + 6 = 12
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3 years ago
Based only on the information given in the diagram, which congruence theorems or postulates could be given as reasons why HEL PM
nalin [4]
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6 0
3 years ago
(8x^3 - x) - (10x - 5x^2 - 3x^3) <br> Show your work.
sergeinik [125]

Let's simplify step-by-step.
8
x
3
−
x
−
(
10
x
−
5
x
2
−
3
x
3
)
Distribute the Negative Sign:
=
8
x
3
−
x
+
−
1
(
10
x
−
5
x
2
−
3
x
3
)
=
8
x
3
+
−
x
+
−
1
(
10
x
)
+
−
1
(
−
5
x
2
)
+
−
1
(
−
3
x
3
)
=
8
x
3
+
−
x
+
−
10
x
+
5
x
2
+
3
x
3
Combine Like Terms:
=
8
x
3
+
−
x
+
−
10
x
+
5
x
2
+
3
x
3
=
(
8
x
3
+
3
x
3
)
+
(
5
x
2
)
+
(
−
x
+
−
10
x
)
=
11
x
3
+
5
x
2
+
−
11
x
Answer:
=
11
x
3
+
5
x
2
−
11
x


Brainliest Please:)
6 0
3 years ago
Read 2 more answers
Find x (in degrees) in the following quadrilateral.
Ber [7]

Answer:

x = 110°

Step-by-step explanation:

The sum of the interior angles in a quadrilateral is 360°. This means:

x + x + x - 30 + 1/2x + 5 = 360° - we can simplify this

3 1/2x - 25 = 360° - now add 25 to both sides

3 1/2x = 385 - finally divide both sides by 3 1/2

x = 385 ÷ 3.5 = 110

x = 110°

Hope this helps!

5 0
2 years ago
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