Question

Assume you are working with a standard deck of 52 cards. There are 13 cards (2, 3, 4, 5, 6, 7, 8, 9, 10, jack, queen, king, and ace) in each of four suits (clubs, diamonds, hearts, and spades). What is P(9 ∪ Queen) if you draw one card?
0
2/13
7/52
4/13

Answer 1

Answer:

$P(9\cup queen)=\frac{2}{13}$

Step-by-step explanation:

Total number of cards$=52$

Total cards of $9$$=4(1\ club,1\ diamond,1\ heart,1\ spades)$

Total cards of Queen$=4(1\ club,1\ diamond,1\ heart,1\ spades)$

Total number of elements in $9\cup Queen$$=8$

$P(9\cup queen)=\frac{elements\ in\ 9\cup queen}{Total\ number\ of\ elements}\\\\P(9\cup queen)=\frac{8}{52}=\frac{2}{13}$