The answer is B, as a solid and a low temperature would result in the lowest entropy value
Do a quick conversion: 1 grams Co2 = 0.0084841820909097 mole using the molecular weight calculator and the molar mass of Co2.
Answer is: D. 6.02 x 1023.
Because this is Avogadro constant<span> (the number of </span>constituent particles, in this example atoms of gold<span> that are contained in the </span>amount of substance<span> given by one </span>mole). <span>The </span>mole<span> is the </span>unit of measurement<span> for </span>amount of substance, t<span>he mole is an </span>SI base unit<span>, with the unit symbol </span>mol<span>.</span>
Answer:
45.0 L is the volume of gas will the balloon contain at 1.35 atm and 253 K.
Explanation:
Using Ideal gas equation for same mole of gas as
Given ,
V₁ = 25.0 L
V₂ = ?
P₁ = 2575 mm Hg
Also, P (atm) = P (mm Hg) / 760
P₁ = 2575 / 760 atm = 3.39 atm
P₂ = 1.35 atm
T₁ = 353 K
T₂ = 253 K
Using above equation as:

Solving for V₂ , we get:
<u>V₂ = 45.0 L</u>
45.0 L is the volume of gas will the balloon contain at 1.35 atm and 253 K.