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Eva8 [605]
3 years ago
14

Calcium carbonate can be decomposed by heating: CaCO3 - CaO + CO2

Chemistry
1 answer:
Galina-37 [17]3 years ago
3 0

Answer: 13.888g

Explanation:

CaCO3 —> CaO + CO2

From the equation above, 1mole of CaCO3 produces 1mole of CaO. Since the answer is to be expressed in grams, let us covert this mole to grams. This is illustrated below:

MM of CaCO3 = 40 +12 + (16x3) = 40 + 12 + 48 = 100g/mol

MM of CaO = 40 + 16 = 56g/mol

From the equation,

100g of CaCO3 produced 56g CaO

Therefore, 24.8g of CaCO3 will produce Xg of CaO i.e

Xg of CaO = (24.8 x 56) / 100 = 13.888g

Therefore, the theoretical yield of CaO is 13.888g

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1) ZnBr₂ (aq) + AgNO₃ (aq)

Chemical equation:

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Balanced chemical equation:

ZnBr₂ (aq) + 2AgNO₃ (aq)  →Zn(NO₃)₂(aq) + 2AgBr(s)

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Zn²⁺(aq) + Br₂²⁻ (aq) + 2Ag⁺ (aq)+ 2NO⁻₃ (aq)  → Zn²⁺(aq) +(NO₃)₂²⁻(aq) + 2AgBr(s)

Net ionic equation:

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The Zn²⁺((aq) and NO⁻₃ (aq) are spectator ions that's why these are not written in net ionic equation. The AgBr can not be splitted into ions because it is present in solid form.

Spectator ions:

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2) HgCl₂ (aq) + KI (aq)  →

Chemical equation:

HgCl₂ (aq) + KI (aq)  → KCl + HgI₂

Balanced chemical equation:

HgCl₂ (aq) + 2KI (aq)  → 2KCl(aq) + HgI₂(s)

Ionic equation:

Hg²⁺(aq)  + Cl₂²⁻  (aq) + 2K⁺(aq) + 2I⁻ (aq)  →  HgI₂ (s) + 2K⁺(aq) + 2Cl⁻ (aq)

Net ionic equation:

Hg²⁺(aq)  + 2I⁻ (aq) →   HgI₂ (s)

The Cl⁻ ((aq)  and K⁺ (aq) are spectator ions that's why these are not written in net ionic equation. The HgI₂ (s) can not be splitted into ions because it is present in solid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.

 

3) Ca(OH)₂ (aq) + Na₂SO₄ (aq)

Chemical equation:

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Balanced chemical equation:

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Ionic equation:

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Net ionic equation:

Ca²⁺(aq)   + SO₄²⁻ (aq)  →   CaSO₄(s)

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Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.

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