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3 years ago

Which of these correctly defines the pOH of a solution? a.) pOH=log[H3O+] b.) pOH=-log[H30+] c.) pOH=log[OH-] d.) pOH=-log[OH-]

1 answer:

3 0

The answer is d) pOH = - lg[OH-]. Like pH expression: pH = -lg[H+] or pH = - lg[H3O+]. The pOH is a definition similar to the pH. So the expression is also similar. We only need to change H+ to OH-.

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What is the concentration of a dextrose solution prepared by diluting 16 mL of a 1.0 M dextrose solution to 25 mL using a 25 mL

seraphim [82]

Answer:

0.64 M

Explanation:

Step 1: Given data

Initial concentration (C₁): 1.0 M

Initial volume (V₁): 16 mL

Final concentration (C₂): ?

Final volume (V₂): 25 mL

Step 2: Calculate the final concentration of the dextrose solution

We want to prepare a diluted solution from a concentrated one. We can find the final concentration using the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁ / V₂

C₂ = 1.0 M × 16 mL / 25 mL

C₂ = 0.64 M

4 0

3 years ago

which of the following antibiotic products may cause a cross sensitivity reaction in patients who are allergic to penicillin?

Dominik [7]

Answer:

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Explanation:

3 0

3 years ago

Read 2 more answers

What is the classification of a solution of naoh with a ph of 8.3?

Maksim231197 [3]

Answer:

<u>Alkaline or basic solution </u>(alkaline and basic means the same)

Explanation:

According to the <em>pH</em>, solutions may be classified as neutral, acidic, or alkaline (basic).

This table shows such classification:

pH classification

7 neutral

> 7 alkaline or basic

< 7 acidic

Thus, since the pH of the solution is 8.3, which is greater than 7, the solution is classified as basic (alkaline).

Additionally, you must learn that pH is a logarithmic scale for the concentration of hydronium ions in the solution.

pH = - log [H₃O⁺]

You can calculate the concentration of hydronium ions using antilogarithm properties:

$pH=-log[H_3O^+]\\ \\ {[H_3O^+]}=10^{-pH}\\ \\ {[H_3O^+]}=10^{-8.3}=0.00000000501$

NaOH solutions are alkaline solutions, bases, according to Arrhenius model, because they contain OH⁻ ions and release them when ionize in water.

8 0

3 years ago

How many grams are in 11.9 moles of chromirum

faust18 [17]

Answer:

Explanation:

Method 1 proportion

1 mole of chromium is 52 grams

11.9 moles = x grams

1/11.9 = 52/x Cross multiply

x = 11.9 * 52

x = 618.8 grams

Now I have used an approximate mass for Chromium. The answer you get here is expected to reflect the weigth given on your periodic table Use that to get your answer. You should give a number very close to mine. Round to 3 places as in 619.

Method Two Formula

mols = given mass / molecular mass

11.9 = given mass / 51.9961 Multiply both sides by 51.9961

11.9 *51.9961 = given mass

given mass = 618.75

given mass = 619

3 0

3 years ago

A solution is prepared by mixing 50.0 mL toluene (C6H5CH3 d=0.867 g/mL) with 125 mL Benzene (C6H6 d=0.874 g/mL). Assuming that t

Tatiana [17]

Answer:

mass % = 28.4%

mole fraction = 0.252

molality = 3.08 molal

molarity = 2.69 M

Explanation:

Step 1: Data given

Volume of toluene = 50.0 mL = 0.05 L

Density toluene = 0.867 g/mL

Molar mass toluene = 92.14 g/mol

Volume of benzene = 125 mL = 0.125 L

Density benzene = 0.874 g/mL

Molar mass benzene = 78.11 g/mol

Step 2: Calculate masses

Mass = density * volume

Mass toluene = 50.0 mL * 0.867 g/mL = 43.35 g

Mass benzene = 125 mL * 0.874 g/mL = 109.25 g

Step 3: Calculate number of moles

Moles = mass / molar mass

Moles toluene = 43.35 grams /92.14 g/mol = 0.470 5 moles

Moles benzene = 109.25 grams / 78.11 g/mol = 1.399 moles

Step 4: Calculate molarity of toluene

Molarity = moles / volume

Molarity toluene = 0.4705 moles / 0.175 L = 2.69 M

Step 5: Calculate mass % of toluene

Mass % = (43.35 grams / (43.35 + 109.25) )*100 % = 28.4 %

Step 6: Calculate mole fraction of toluene

Mole fraction toluene = Moles toluene / total number of moles

Mole fraction toluene = 0.4705 / (0.4705 + 1.399) = 0.252

Step 7: Molality of toluene

Molality = number of moles / mass

Molality of toluene = 0.4705 moles / (0.04335 + 0.10925)

Molality of toluene = 3.08 molal

4 0

3 years ago