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luda_lava [24]
3 years ago
8

When a lead acid car battery is recharged by the alternator, it acts essentially as an electrolytic cell in which solid lead(II)

sulfate PbSO4 is reduced to lead at the cathode and oxidized to solid lead(II) oxide PbO at the anode. Suppose a current of 17.0A is fed into a car battery for 15.0 seconds. Calculate the mass of lead deposited on the cathode of the battery. Be sure your answer has a unit symbol and the correct number of significant digits.
Chemistry
1 answer:
zysi [14]3 years ago
7 0

Answer:

0.273504 grams

Explanation:

Charge Deposited = Current ×Time

q=It

Given: I= 17.0A, t= 15.0 seconds

Q= 17×15= 255 C

Since, 1 mole contains 96500C of charge deposition

Therefore, number of moles = 255/96500 = 0.00264 moles

Moreover, since Pb changes to Pb2+,

Hence number of moles of Pb deposited = 0.00264/2

= 0.00132

Also, Molar mass of Lead = 207.2 gm/mol

Therefore, the mass of lead deposited = 0.00132×207.2 = 0.273504 grams

.

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Ammonia (NH3) reacts with sulfuric acid to form ammonium sulfate. How many grams of ammonium sulfate are obtained from 8.73 g of
Gwar [14]
I hope you understand my working:
1) Finding the mol of NH3 to find the mol of (NH4)2SO4 (ammonium sulfate)
2) Mr of (NH4)2SO4
3) Theoretical yield: The actual grams of (NH4)2SO4 produced when reacting 0.514 mol of NH3 to 0.514 mol H2SO4
4) Using formula of (given grams)/(theoretical grams or actual grams) * 100 = 73%
5) Basic algebra

4 0
3 years ago
NEED HELP ASAP!!!!!!!!!!!!!!!!!!!!!!
Paraphin [41]
<h2>Answer:  C) 1s²2s²2p⁶</h2>

<h3>Explanation:</h3>

A noble gas has 8 electrons between the p and s orbitals of the outer shell. Helium is the exception because it only has two electrons.

<h3>                       ∴  1s²2s²2p⁶ is the noble gas (neon)</h3>

7 0
3 years ago
Why did workers form labor unions?
USPshnik [31]

Answer:

Labor unions were created in order to help the workers with work-related difficulties such as low pay, unsafe or unsanitary working conditions, long hours, and other situations. ... Sometimes the unions organized strikes in order to try to change the conditions of the workers.

Explanation:

5 0
3 years ago
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How many moles is 22.4 liters of oxygen gas at standard temperature and pressure represent
makkiz [27]

Answer:

So 1 mole

Explanation:

PV = nRT

P = Pressure atm

V = Volume L

n = Moles

R = 0.08206 L·atm·mol−1·K−1.

T = Temperature K

standard temperature = 273K

standard pressure = 1 atm

22.4 liters of oxygen

Ok so we have

V = 22.4

P = 1 atm

PV = nRT

n = PV/RT

n = 22.4/(0.08206 x 273)

n  = 22.4/22.40

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7 0
3 years ago
With 21 g of Zinc, and 7 g of CuCl2, how much ZnCl2 is made in grams?
mina [271]

Answer: 7.07 grams

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}\times{\text{Molar Mass}}    

\text{Moles of} zinc=\frac{21g}{65g/mol}=0.32moles

\text{Moles of} CuCl_2=\frac{7g}{134g/mol}=0.052moles

Zn+CuCl_2\rightarrow Cu+ZnCl_2

According to stoichiometry :

1 mole of CuCl_2 require 1 mole of Zn

Thus 0.052 moles of CuCl_2 will require=\frac{1}{1}\times 0.052=0.052moles  of Zn

Thus CuCl_2 is the limiting reagent as it limits the formation of product and Zn is the excess reagent.

As 1 mole of CuCl_2 give = 1 mole of ZnCl_2

Thus 0.052 moles of CuCl_2 give =\frac{1}{1}\times 0.052=0.052moles  of ZnCl_2

Mass of ZnCl_2=moles\times {\text {Molar mass}}=0.052moles\times 136g/mol=7.07g

Thus 7.07 g of ZnCl_2 will be produced from the given masses of both reactants.

8 0
3 years ago
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