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pav-90 [236]
3 years ago
5

Coach Walker wants to buy equal numbers of footballs and basketballs for her PE class. The footballs cost $9 each, and the baske

tballs cost $7 each. Coach Walker has $208 for the purchase. How many of each type of ball can she buy?
Mathematics
1 answer:
DENIUS [597]3 years ago
8 0

Answer:

13 footballs and 13 basketballs

Step-by-step explanation:

Let f = footballs

b = basketballs

f=b since we are buying an equal number

9f+7b = 208

Substitute f=b

9f+7f = 208

16f = 208

Divide by 16

16f/16 = 208/16

f=13

We are buying 13 footballs

Since f=b

We are buying 13 basketballs

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Find the value of 4x2 – 2y when x = 3 and y = 2.
Alina [70]

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4(3)2-2(2)

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3 years ago
Dennis is going to use a number line to multiply 6 × 4.
Sergeeva-Olga [200]
B. The answer will always be to the right of 4.
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If we list all the natural numbers below 20 that are multiples of 7 or 11, we get 7, 11 and 14. The sum of these multiples is 32
velikii [3]
Number of multiples of 7 up to 1337: \left\lfloor\dfrac{1337}7\right\rfloor=191
Number of multiples of 11 up to 1337: \left\lfloor\dfrac{1337}{11}\right\rfloor=121
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This means there are 191+121-17=295 distinct multiples of 7 *or* 11 up to 1337.

The sum of these multiples is

\displaystyle\sum_{k=1}^{191}7k+\sum_{k=1}^{121}11k-\sum_{k=1}^{17}77k

which can be computed using the well-known formula,

\displaystyle\sum_{k=1}^nk=\dfrac{n(n+1)}2

So you have

\displaystyle\sum_{k=1}^{191}7k+\sum_{k=1}^{121}11k-\sum_{k=1}^{17}77k=7\dfrac{191\times192}2+11\dfrac{121\times122}2-77\dfrac{17\times18}2=197762
8 0
3 years ago
01:59:51
IceJOKER [234]

Answer:

L+2=8

Step by step explaintion.

the length is so much longer than some multiple of the width

or perhaps the area of the rectangle.

8 0
3 years ago
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