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jarptica [38.1K]
3 years ago
6

if your hot pack requires 3.0g of a solid to obtain the correct temperature change, instead of the correct amount (1.4g) calcula

te the percent error
Chemistry
1 answer:
gregori [183]3 years ago
6 0

114.3%

Explanation:

Given parameters:

True amount of solid = 1.4g

Measured amount  = 3.0g

Unknown:

Percentage error = ?

Solution:

The inaccuracy in the reading is termed uncertainty.

This is the error.

 Error  = true  value - measured value.

   The values of errors are absolute.

Percentage error = \frac{|true value - measured value|}{true value}  x 100

Percentage error = \frac{1.4 - 3}{1.4} x 100 = 114.3%

This is large amount of error

learn more:

Error brainly.com/question/2764830

#learnwithBrainly

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Consider four different samples: aqueous LiBr , molten LiBr , aqueous AgBr , and molten AgBr . Current run through each sample p
Charra [1.4K]

Answer:

a) Aqueous LiBr = Hydrogen Gas

b) Aqueous AgBr = solid Ag

c) Molten LiBr = solid Li

c) Molten AgBr = Solid Ag

Explanation:

a) Aqueous LiBr

This sample produces Hydrogen gas, because the H+ (conteined in the water) has a reduction potential higher than the Li+ from the salt. Therefore the hydrogen cation will reduce instead of the lithium one and form the gas.

b) Aqueous AgBr

This sample produces Solid Ag, because the Ag+ has a reduction potential higher than the H+ from the water. Therefore the silver cation will reduce instead of the hydrogen one and form the solid.

c) Molten LiBr

In a molten binary salt like LiBr there is only one cation present in the cathod. In this case the Li+, so it will reduce and form solid Li.  

c) Molten AgBr

The same as the item above: there is only one cation present in the cathod. In this case the Ag+, so it will reduce and form solid Ag.  

6 0
3 years ago
23.5 L of h2 is stored at a pressure of 58.7 Kpa what volume would the gas take up at stp
stepan [7]

Answer:-  13.6 L

Solution:- Volume of hydrogen gas at 58.7 Kpa is given as 23.5 L. It asks to calculate the volume of hydrogen gas at STP that is standard temperature and pressure. Since the problem does not talk about the original temperature so we would assume the constant temperature. So, it is Boyle's law.

Standard pressure is 1 atm that is 101.325 Kpa.

Boyle's law equation is:

P_1V_1=P_2V_2

From given information:-

P_1 = 58.7 Kpa

V_1 = 23.5 L

P_2 = 101.325 Kpa

V_2 = ?

Let's plug in the values and solve it for final volume.

58.7Kpa*23.5L=101.325Kpa*V_2

On rearranging the equation for V_2

V_2=\frac{58.7Kpa*23.5L}{101.325Kpa}

V_2 = 13.6 L

So, the volume of hydrogen gas at STP for the given information is 13.6 L.

3 0
3 years ago
An iminium ion is formed as an intermediate in a stork enamine reaction. the iminium is subsequently hydrolyzed with water. comp
Dvinal [7]
Below is the mechanism showing the hydrolysis of Iminium Ion into aldehye. The arrows are shown in RED.

7 0
3 years ago
How many valence electrons does strontium (Sr) have?
Arisa [49]
Two valence electrons
5 0
3 years ago
When aluminum is placed in concentrated hydrochloric acid, hydrogen gas is produced. 2 Al ( s ) + 6 HCl ( aq ) ⟶ 2 AlCl 3 ( aq )
Dovator [93]

Answer:

The volume of hydrogen gas produced at STP is 4.90 liters.

Explanation:

2Al (s) + 6 HCl (aq)\rightarrow 2 AlCl_3 (aq) + 3 H_2 (g)

Moles of aluminium =\frac{3.60 g}{27 g/mol}=0.1333 mol

According to reaction , 2 moles of aluminium gives 3 moles of hydrogen gas.

Then 0.1333 moles of aluminium will give:

\frac{3}{2}\times 0.1333 mol=0.2 moles of hydrogen gas

Volume of 0.2 moles of hydrogen gas at STP = V

Temperature at STP = T = 298.15 K

Pressure at STP = P = 1 atm

n = 0.2 mol

PV = nRT (Ideal gas equation)

V=\frac{nRT}{P}=\frac{0.2mol\times 0.0821 atm L/mol K\times 298.15 K}{1 atm}=4.8956 L\approx 4.90 L

The volume of hydrogen gas produced at STP is 4.90 liters.

4 0
3 years ago
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