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jarptica [38.1K]
3 years ago
6

if your hot pack requires 3.0g of a solid to obtain the correct temperature change, instead of the correct amount (1.4g) calcula

te the percent error
Chemistry
1 answer:
gregori [183]3 years ago
6 0

114.3%

Explanation:

Given parameters:

True amount of solid = 1.4g

Measured amount  = 3.0g

Unknown:

Percentage error = ?

Solution:

The inaccuracy in the reading is termed uncertainty.

This is the error.

 Error  = true  value - measured value.

   The values of errors are absolute.

Percentage error = \frac{|true value - measured value|}{true value}  x 100

Percentage error = \frac{1.4 - 3}{1.4} x 100 = 114.3%

This is large amount of error

learn more:

Error brainly.com/question/2764830

#learnwithBrainly

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Answer:

56.9 mmoles of acetate are required in this buffer

Explanation:

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CH₃COOH  +  H₂O  ⇄   CH₃COO⁻  +  H₃O⁺     Ka

We know that Ka from acetic acid is: 1.8×10⁻⁵

pKa = - log Ka

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We replace data:

5.5 = 4.74 + log ([acetate] / 10 mmol)

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An alloy with an average grain diameter of 35 μm has a yield strength of 163 Mpa, and when it undergoes strain hardening, the gr
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Answer:

\sigma_y\ =210.2\ MPa  

Explanation:

Given that

d= 35 μm ,yield strength = 163 MPa

d= 17 μm ,yield strength = 192 MPa

As we know that relationship between diameter and yield strength

\sigma_y=\sigma_o+\dfrac{K}{\sqrt d}

\sigma_y\ =Yield\ strength

d = diameter

K =Constant

\sigma_o\ =material\ constant

So now by putting the values

d= 35 μm ,yield strength = 163 MPa

163=\sigma_o+\dfrac{K}{\sqrt 35}      ------------1

d= 17 μm ,yield strength = 192 MPa

192=\sigma_o+\dfrac{K}{\sqrt 17}           ------------2

From equation 1 and 2

192-163=\dfrac{K}{\sqrt 17}-\dfrac{K}{\sqrt 35}

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By putting the values of K in equation 1

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Now when d= 12 μm

\sigma_y=96.31+\dfrac{394.53}{\sqrt 12}

\sigma_y\ =210.2\ MPa

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