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siniylev [52]
1 year ago
12

Ions in solution are found in a hydration shell of water. This shell must be removed for an ion to pass through the channel. How

does the K channel accomplish removal of the water from the shell around the ion
Chemistry
1 answer:
kirill [66]1 year ago
6 0

The K+ channel uses the energy in ATP hydrolysis to remove the hydration shell from the K+ion

All of this truly implies is that one of these bonds breaks in a hydrolysis process (a water-mediated breakdown reaction), releasing a sizable amount of energy.

The following reaction results in the hydrolysis of ATP to ADP:

ATP+H2O⇋ADP+Pi+energy

The hydrolysis of ATP to ADP is reversible, like the majority of chemical processes.

Energy is needed for the reverse process, which creates ATP from ADP and Pitext P iPi start subscript, P, end subscript, start subscript, I end subscript.

Because cells frequently use (hydrolyze) ATP molecules and depend on constant production of replacement ATP, ATP regeneration is crucial1^1.

Hence the  K+ channel uses the energy in ATP hydrolysis to remove the hydration shell from the K+ion

Learn more about hydrolysis here:

brainly.com/question/4352413

#SPJ4

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How many moles of AIC3 are there in 1,119.972 g ?
Alchen [17]

Answer:

it is 8.40189 moles of AlCl3

mole = mass/molar mass

mole= 1119.972/133.34

6 0
3 years ago
The picture below is a great example of __________ biodiversity.
ss7ja [257]
Low because it is not diverse. It is just seed corn.
6 0
2 years ago
Summarize the relationship between volume, temperature and pressure (use words like “inversely
Alinara [238K]

Answer:

P and V: inversely proportional

P and T: directly proportional

V and T: inversely proportional

Explanation:

For pressure and volume, as the volume goes up, meaning the container gets bigger, the pressure would go down. There would be more room in the container, so there would be less collisions between the molecules themselves and between the molecules and the container. This makes them inversely proportional.

For pressure and temperature, as the pressure goes up, there are more collisions, so the particles move faster. Temperature is the speed of the particles, so, since both pressure and temperature would go up at the same time, they are directly proportional.

For volume and temperature, this is similar to the PV relationship. As volume increases, there are less collisions between the particles. This means that the particles are going to move slower. Therefore, as volume goes up, temperature goes down, so they are inversely proportional.

Sorry this is super long, but I hope it fully explains the question for you! ☺

4 0
3 years ago
What is the density of aluminum in grams per cubic centimeter?
oksano4ka [1.4K]

Answer:

Density of aluminum is 2.699 g/cm^3

Explanation:

Density of a given material can be defined as the mass of the substance present in a unit volume. Mathematically it can be expressed as:

Density = \frac{Mass}{Volume}

Units: g/cm^3 or kg/m^3

Aluminum (Al) is one the lightest element and is known to have a density of 2.699 g/cm^3

5 0
2 years ago
Calculate the unit cell edge length for an 85 wt% fe-15 wt% v alloy. All of the vanadium is in solid solution, and, at room temp
Lady bird [3.3K]

Answer is 0.289nm.

Explanation: The wt % of Fe and wt % of V is given for a Fe-V alloy.

wt % of Fe in Fe-V alloy = 85%

wt % of V in Fe-V alloy = 15%

We need to calculate edge length of the unit cell having bcc structure.

Using density formula,

\rho_{ave}=\frac{Z\times M_{ave}}{a^3\times N_A}

For calculating edge length,

a=(\frac{Z\times M_{ave}}{\rho_{ave}\times N_A})^{1/3}

For calculating M_{ave}, we use the formula

M_{ave}= \frac{100}{\frac{(wt\%)_{Fe}}{M_{Fe}}+\frac{(wt\%)_{V}}{M_V}}

Similarly for calculating (\rho)_{ave}, we use the formula

\rho_{ave}= \frac{100}{\frac{(wt\%)_{Fe}}{\rho_{Fe}}+\frac{(wt\%)_{V}}{\rho_V}}

From the periodic table, masses of the two elements can be written

M_{Fe}= 55.85g/mol

M_{V}=50.941g/mol

Specific density of both the elements are

(\rho)_{Fe}=7.874g/cm^3\\(\rho)_{V}=6.10g/cm^3

Putting  M_{ave} and \rho_{ave} formula's in edge length formula, we get

a=\left [\frac{Z\left (\frac{100}{\frac{(wt\%)_{Fe}}{M_{Fe}}+\frac{(wt\%)_{Fe}}{M_{Fe}}}  \right )}{N_A\left (\frac{100}{\frac{(wt\%)_V}{\rho_V}+\frac{(wt\%)_V}{\rho_V}}  \right )}  \right ]^{1/3}

a=\left [\frac{2atoms/\text{unit cell}\left (\frac{100}{\frac{85\%}{55.85g/mol}+\frac{15\%}{50.941g/mol}}  \right )}{(6.023\times10^{23}atoms/mol)\left (\frac{100}{\frac{85\%}{7.874g/cm^3}+\frac{15\%}{6.10g/cm^3}}  \right )}  \right ]^{1/3}

By calculating, we get

a=2.89\times10^{-8}cm=0.289nm

7 0
2 years ago
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