<u>Given</u>:
Four lines are marked proportion, the length of TW can be determined by

<u>Value of a:</u>
Let us set the proportion for the given lines.
Thus, we have;



Thus, the value of a is 5.6
<u>Value of b:</u>
Let us set the proportion for the given lines.
Thus, we have;



Thus, the value of b is 5.
<u>Length of TW:</u>
The length of TW is given by


Thus, the length of TW is 13.6
The probability that all marbles are yellow is
(7/20) (7/20) (7/20) = 343/8000
We are given
x = 2 and 3
u = 2.5
s = 0.5
Getting the z score
z = (2 - 2.5) / 0.5 and (3 - 2.5)/ 0.5
z = -1 and 1
The percentage is
1 - 0.1557 = 81.5%
Let's begin ! ^_^
You have got informations in your problem that you just have to translate in a "mathematic language".
Company A :
"$40 membership fee and $2 per video stream."
Thanks to that, you can guess :
c = 40 + 2s
Now let's do the same thing to the company B.
Company B :
"charges a one-time $20 membership fee and $4 per video stream."
Therefore, c = 20 + 4s.
I think you have guessed !! =D And yes the system of equation that you have to solve and you're looking for is :
{c=40+2s ( Option B)
c=20+4s.
Second step : For how many video streams will the cost be the same for both companies?
We just have to solve the system :) And there is only one variable, the letter "s".
We know that we have to find equal costs as it is said in the question " the cost be the same for both companies", so :
=> 40 + 2s = 20 +4s
=> 4s - 2s = 40 - 20
=> 2s = 20
=> s = 20/2
=> s = 10
Verification :
Company A :
=> 40 + 2s = 40 + 2*10 = 40 + 20 =60.
Company B :
=> 20 + 4s = 20 + 4*10 = 20 + 40 = 60
As you have seen, the costs are the same for both companies.
We can say that as a conclusion for 10 video streams, the cost will be the same for both companies.
In short, the answer would be : 10.
Let me give you an advice : Usually the word "per" means a multiplication is the mathematic language.
Hope this helps !
Photon
Answer:
a) Total 16 possibilities
MMMM
FFFF
MMMF
MMFM
MFMM
FMMM
FFFM
FFMF
FMFF
MFFF
MMFF
MFMF
MFFM
FFMM
FMMF
FMFM
b) P(MMMM) = 1/16