Remark
It is not a straight line distance from the park to the mall. None of the answers give you that result. And if you know what displacement is, none of the answers are really displacement either. The distance is sort of a "as the crow flies." distance. There's a stop off in the middle of town.
Method
You need to use the Pythagorean Formula twice -- once from the park to the city Center and once from the city center to the mall.
Distance from the Park to the city center.
a = 3 [distance east]
b = 4 [distance south]
c = ??
c^2 = 3^2 + 4^2 Take the square root of both sides.
c = sqrt(3^2 + 4^2)
c = sqrt(9 + 16) Add
c = sqrt(25)
c = 5
So the distance from the park to the city center is 5 miles
Distance from City center to the mall
a = 2 miles [distance east]
b = 2 miles [distance north]
c = ??
c^2 = a^2 + b^2 Substitute
c^2 = 2^2 + 2^2 Expand this.
c^2 = 4 + 4
c^2 = 8 Take the square root of both sides.
sqrt(c^2) = sqrt(8)
c = sqrt(8) This is the result
c = 2.8
Answer
Total distance = 5 + 2.8 = 7.8
Answer:
The surface area is 
Step-by-step explanation:
we know that
The surface area of a square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces.
so
![SA=b^{2}+4[\frac{1}{2}(b)(l)]](https://tex.z-dn.net/?f=SA%3Db%5E%7B2%7D%2B4%5B%5Cfrac%7B1%7D%7B2%7D%28b%29%28l%29%5D)
we have
substitute the values
![SA=0.4^{2}+4[\frac{1}{2}(0.4)(0.6)]=0.64\ m^{2}](https://tex.z-dn.net/?f=SA%3D0.4%5E%7B2%7D%2B4%5B%5Cfrac%7B1%7D%7B2%7D%280.4%29%280.6%29%5D%3D0.64%5C%20m%5E%7B2%7D)
Slope = (5+7)/(1-4) = 12/-3 = -4
slope = -4
y = mx + b
-7 = -4(4) + b
-7 = -16 + b
b = 9
equation
y = -4x + 9
Answer:
0.85
Step-by-step explanation:
6.80 divied by 8
Answer:
The tree is 17.5 ft tall
Step-by-step explanation:
We can use proportions to solve this.
Notice that Emily (5 feet tall) and her shadow (8 feet long) constitute the two legs of a right angle triangle (see attached image).
The nearby tree (unknown height H), will also cast a shadow (28 ft long) with the same inclination as Emily does due to the unique position of the sun relative to them.
Then we can use the proportion associated with the sides of similar triangles:
Then, we can solve for H in the equation:
