Answer:
1/12
Step-by-step explanation:
multiple of 3 and a multiple of 4 implies it can only be 12.
Since you only have the numbers from 1 to 12,
the prob(the 12) = 1/12
To solve for x just isolate x by moving the other variables so....:
First add c to both sides
g+c= y+x
Subtract y from both sides
g+c-y= x
That should be your final answer (we cannot come up with an actual digit for x because there are no numbers in this equation we simply can make an equation for x)
F(x) = (x² - 3x - 10)(x + 4) becomes (x - 5)(x + 2)(x + 4) when completely factored. Now set each binomial equal to zero.
x - 5 = 0
x = 5
x + 2 = 0
x = - 2
x + 4 = 0
x = - 4
Your zeros are at x = - 4, - 2, and 5. Or at (- 4, 0), (- 2, 0), and (5, 0).
We can set up an equation to solve this problem. I am setting the number of marbles in a red jar to R.
R + R + R - 16 = 41
We solve this by adding 16 to both sides and combining all of the R terms.. This gives us:
3R = 57
We can finish this problem by dividing both sides by 3.
R = 19. So, there are 19 marbles in a red jar.
We can easily figure out how many marbles are in a blue jar by subtracting the total amount of marbles in 2 red jars from the total amount of marbles. I am setting the amount of marbles in a blue jar to B.
41 - 19*2 = B
B = 3
So, there are 3 marbles in a blue jar and 19 marbles in a red jar.
Answer:
Step-by-step explanation:
We can add the two equations to eliminate 
and solve for 
.
Now, we can find for by using substitution:
(given)
Hope this helps :)
