Question

What is the solution to: T/t-4=t+4/6

Answer 1

$\frac{t}{t-4}= \frac{t+4}{6} \\ t \neq 4 \\ 6t= (t+4)(t-4) \\ 6t=t^2-16 \\ t^2-6t-16=0 \\ D=b^2-4ac=(-6)^2-4*1*(-16)=36+64=100 \\ t_{1,2}= \frac{-bб \sqrt{D} }{2a} \\ t_1= \frac{6-10}{2}=-2 \\ \ t_2= \frac{6+10}{2}=8$

Answer: t=-2, t=8