Answer:
A polynomial of degree 3 has 3 linear factors… (1): (x - i ) (x + i ) (x + a) . If any 2 factors are conjugate as here first 2 factors are conjugate with complex roots. So at least one root should be real.
Step-by-step explanation:
Start by looking at the vertex form of a quadratic function, f(x) = a(x - h)^2 + k. The variables h and k are the values of the vertex. Plug those in to get f(x) = a(x - 4)^2 + 5. To find the variable a, plug in the point given for the x and y values. So, you get (21) = a((8) - 4)^2 + 5. Solve for a algebraically, and you get a = 1. Finally, plug everything in and simplify the equation. You should get that the quadratic function is f(x) = x^2 - 8x + 21. Hope this helps!
Answer:
The second alternative is correct
Step-by-step explanation:
We have been given the expression;

The above expression can be re-written as;

On the other hand;
![y^{\frac{1}{3}}=\sqrt[3]{y}](https://tex.z-dn.net/?f=y%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7By%7D)
Therefore, we have;
![x^{9}\sqrt[3]{y}](https://tex.z-dn.net/?f=x%5E%7B9%7D%5Csqrt%5B3%5D%7By%7D)
Answer:

Step-by-step explanation:
Equation of the Quadratic Function
The vertex form of the quadratic function has the following equation:

Where (h, k) is the vertex of the parabola that results when plotting the function, and a is a coefficient different from zero.
It's been given the vertex of the parabola as (-2,18):

Now substitute the point (-5,0) and find the value of a:

Operating:


Solving for a:

a = -2
Thus, the equation of the quadratic function is:

The answer is
(x+10)(x-3)