The length of the longer leg of a right triangle is 19ft more than five times the length of the shorter leg. the length of the h
ypotenuse is 20ft more than five times the length of the shorter leg. find the side lengths of the triangle.
1 answer:
Let x represent the length of the shorter leg.
Longer leg: 5x +19
Hypotenuse: 5x +20
Pythagorean theorem:
.. x^2 +(5x +19)^2 = (5x +20)^2
.. x^2 +25x^2 +190x +19^2 = 25x^2 +200x +20^2 . . . . . . eliminate parentheses
.. x^2 -10x -39 = 0
.. (x -13)(x +3) = 0
.. x = 13 . . . . . . . . . . leg lengths must be positive
The side length of the triangle are 13, 84, 85 feet.
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99°
Explanation:
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m∠2 = 55°
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Answer:
12.5a-8.1b
Step-by-step explanation:
Remove the unnecessary parenthesis
14.2+9.8b-(13.1b-2a)-(3.7a+4.8b)
Collect like terms
12.5a+9.8b-13.1b-4.8b
Giving you the answer of: 12.5a-8.1b