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loris [4]
4 years ago
3

5. The sphere shown below is placed in a full overflow cup and sinks to the bottom. How much water is displaced by the sphere?

Chemistry
1 answer:
Lynna [10]4 years ago
5 0

Answer : The correct option is (A) 51.0 mL

Explanation :

As we know that water displaced is equal to the volume of sphere.

Now we have to determine the volume of sphere.

Formula used:

Volume of sphere = \frac{4}{3}\pi r^3

where,

r = radius of sphere

Given:

Diameter of sphere = 4.6 cm

Radius of sphere = \frac{Diameter}{2}=\frac{4.6cm}{2}=2.3cm

So,

Volume of sphere = \frac{4}{3}\times 3.14\times (2.3cm)^3

Volume of sphere = 50.94cm^3\approx 51.0 cm^3

Water displaced = Volume of sphere = 51.0 cm^3

We know that:

1cm^3=1mL

So,

Water displaced = 51.0 mL

Therefore, the correct option is (A) 51.0 mL

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A major component of gasoline is octane . When octane is burned in air, it chemically reacts with oxygen gas to produce carbon d
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Answer:

mass of O₂ = 800 g

Explanation:

Formula of Octane = C₈H₁₈

Formula of Oxygen = O₂

Balanced Chemical Reaction:

Octane react with oxygen and produce water and carbon dioxide.

                    2C₈H₁₈ + 25O₂ ---------> 16CO₂+ 18H₂O

Moles calculation:

From the number of moles of the reactant used in a chemical reaction specific number of product produced. we can find the amount of any reactant and product from the mole ratio of a chemical reaction.

Mole formula =  

no. of moles = mass in grams / molecular mass ............... (1)

Given Data:

Molecular Weight of O₂  =  (16 x2 ) = 32 g/mol

Mass of O₂ = To be find

Calculations:

                             2C₈H₁₈  +  25O₂      --------->  16CO₂   +    18H₂O

                              2mole      25 mole                 16 mole     18 mole

From the above balanced chemical equation it is know that 2 mole of octane consume 25 mole of oxygen.

so we have to calculate the mass of oxygen that is consumed

by using mole formula  (1) we can fine the mass of oxygen

we know

Molecular Weight of O₂  =  32 g/mol

number of moles of Oxygen molecule = 25 mol

putting the value in the below formula

            no. of moles of O₂ = mass of O₂ / molecular mass of O₂

            25 mole = mass of O₂ / 32 g/mol ....... (2)

By rearragming the equation (2)

            mass of O₂ = 25 mole x 32 g/mol

            mass of O₂ = 25 mole x 32 g/mol

            mass of O₂ = 800 g

So in the octan reaction with oxygen 800g of oxygen will use.  

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