The study of atomic structure helps us understand more about the way the universe is constructed, how our bodies are made, and the components of life, which we can apply to other sciences in the fields of: health and disease prevention, fuels, product industry etc... It basically helps us to understand how we can make new things and how to utilize the power of the universe.
Answer:
- <em><u>A. isotopes </u></em>
<em><u></u></em>
Explanation:
The <em>periodic table</em> was organized by Dimitry Mendeleiev by 1869, as he showed the connection between the atomic mass and the properties of the elements.
Nevertheless, the order of some few elements had to be altered because the properties did not follow the order of the atomic masses.
Henry Mosely by 1913 determined that atoms of a same element had different number of neutrons, leading to different atomic masses. These atoms of a same element (with the same number of protons) with different number of neutrons are known as<em> isotopes.</em>
By arranging the elements in increasing order of the number or protons (atomic number), instead of the atomic masses, all the elements resulted ordered according with a repetitive (periodic) pattern of chemical properties.
Answer : The rate of consumption of
is, 
Explanation : Given,
Moles of
= 
Volume of solution = 170 mL = 0.170 L (1 L = 1000 mL)
Time = 170 s
First we have to calculate the concentration.



Now we have to calculate the rate of consumption.



Thus, the rate of consumption of
is, 
Answer:
<h3>
<em /></h3><h3>
<em>Please make sure to re-write this so your teacher doesn't think your cheating!</em></h3>
Explanation:
To write the Potassium electron configuration, we first need to know the number of electrons for the K atom (there are 19 electrons). When we write the configuration we'll put all 29 electrons in orbitals around the nucleus of the Potassium atom.
In the given <span>phase diagram, the line segment that describes the interface between solid and vapor is A-B. The rest of the choices do not answer teh question above</span>